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sashaice [31]
3 years ago
12

A curve has a radius of 50 meters and is banked 5 degrees. The road is covered with ice and is frictionless. What is the maximum

speed, in mph, a car can travel and negotiate the curve? A.) 15.65mph B.) 25.00mph C.)65.00mph D.) 6.55mph E.) None of the above
Physics
1 answer:
Salsk061 [2.6K]3 years ago
8 0

Answer:

E.) None of the above

Explanation:

Draw a free body diagram.  There are two forces acting on the car.  Normal force perpendicular to the road, and weight downward.

Sum of the forces perpendicular to the road:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

Sum of the forces towards the center of the circle:

∑F = ma

N sin θ = mv²/r

mg cos θ sin θ = mv²/r

g cos θ sin θ = v²/r

v = √(gr cos θ sin θ)

Given r = 50 m and θ = 5°:

v = √(9.8 m/s² × 50 m × cos 5° × sin 5°)

v = 6.52 m/s

v = 14.6 mph

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Using the equation zeff=z−s and assuming that core electrons contribute 1.00 and valence electrons contribute 0.00 to the screen
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Thank you for posting your question here at brainly. Below is the solution. I hope the answer will help. 

<span>Cl^- 1s^2 2s^2p^6 3s^2 3p^6 1s^2 2s^2p^6 S = 10; 3s^2 3p^6 S = 0 </span>
<span>Zeff = Z-S = 17- 10 =7 </span>
<span>K^+ 1s^2 2s^2p^6 3s^2 3p^6; 1s^2 2s^2p^6 S = 10; 3s^2 3p^6 S = 0 </span>
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<span>K^+ 1s^2 2s^2p^6 3s^2 3p^6 same S as for Cl^- but Z increases by 2 hence </span>
<span>Zeff(K^+) = 19 - 11.25 = 7.75</span>
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