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sashaice [31]
4 years ago
12

A curve has a radius of 50 meters and is banked 5 degrees. The road is covered with ice and is frictionless. What is the maximum

speed, in mph, a car can travel and negotiate the curve? A.) 15.65mph B.) 25.00mph C.)65.00mph D.) 6.55mph E.) None of the above
Physics
1 answer:
Salsk061 [2.6K]4 years ago
8 0

Answer:

E.) None of the above

Explanation:

Draw a free body diagram.  There are two forces acting on the car.  Normal force perpendicular to the road, and weight downward.

Sum of the forces perpendicular to the road:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

Sum of the forces towards the center of the circle:

∑F = ma

N sin θ = mv²/r

mg cos θ sin θ = mv²/r

g cos θ sin θ = v²/r

v = √(gr cos θ sin θ)

Given r = 50 m and θ = 5°:

v = √(9.8 m/s² × 50 m × cos 5° × sin 5°)

v = 6.52 m/s

v = 14.6 mph

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Identical particles are placed at the 50-cm and 80-cm marks on a meter stick of negligible mass. This rigid body is then mounted
kogti [31]

Answer:

5.35 rad/s

Explanation:

From the question, we are toldthat an Identical particles are placed at the 50-cm and 80-cm marks on a meter stick of negligible mass. This rigid body is then mounted so as to rotate freely about a pivot at the 0-cm mark on the meter stick.

Solving this question, the potential energy of the particles must equal to the Kinectic energy i.e

P.E=K.E

Mgh= m½Iω²-------------eqn(*)

Where M= mass of the particles

g= acceleration due to gravity= 9.81m/s^2

ω= angular speed =?

h= height of the particles in the stick on the metre stick= ( 50cm + 80cm)= (0.5m + 0.8m)= 130cm=1.3m

If we substitute the values into eqn(*) we have

m×9.81× (1.3m)= 1/2× m×[ (0.5m)² + [(0.8m)²]× ω²

m(12.74m²/s²)= 1/2× m× (0.25+0.64)× ω

m(12.74m²/s²)= 1/2× m× 0.89× ω²

We can cancel out "m"

12.74= 1/2×0.89 × ω²

12.74×2= 0.89ω²

25.48= 0.89ω²

ω²= 28.629

ω= √28.629

ω=5.35 rad/s

Hence, the angular speed of the meter stick as it swings through its lowest position is 5.35 rad/s

4 0
3 years ago
What is the size of the smallest vertical plane mirror in which a 6 ft tall person standing erect can see her full-length image?
Elden [556K]

Answer:

3 ft and yh your welcomehajafafjafay

Explanation:

avshusjahsguaraysiagast

avhagfajakawsysjegvdehhshdshnxddjdntdjkrksjjdkrldpsdkdjjrdduuueisuigdrfdddxffddrrdddddssfgdsdddddffghyt

4 0
3 years ago
In tae-kwon-do, a hand is slammed down onto a target at a speed of 14 m/s and comes to a stop during the 3.0 ms collision. Assum
GrogVix [38]

Answer:

A) The impulse is 11,7 kg.m/s .  B) The average force on the hand is 3900N

Explanation:

Givens:

Hand's mass (m)= 0,90kg

Hand's initial velocity (vi)= 14m/s

Time of collision (t)= 3ms

<u>A) Impulse is the change of momentum of an object when the object is acted upon by a force for an interval of time. We use the formula:</u>

<em />

<em>/F/ = m. /Δv/</em>

<u>Where:</u>

F= Force of Impulse

m= Mass

Δv= change in speed ( vf-vi)

Using that formula we get:

/F/= 0,90kg . / (0m/s-14m/s) /

/F/=0,90kg . 14m/s

<em>/F/ = 11,7 kg. m/s</em>

*note that (vf) is 0 because the hand stops in the action, so it's final

velocity = 0

<u>B)The average force is equal to the change in the momentum over the change in time. We use the formula:</u>

<em>/F/= m. (Δv) : Δt</em>

<u>Where:</u>

F= the average force from the target

m= the mass of the hand

Δv= hange in speed (vf/vi)

Δt= change in time

*if we look closely, we find the we alredy have half of the equation because we have alredy calculated m.(Δv) in point A.

We boil the equation down to:

/F/= Impulse : Δt

/F/= 11,7kg.m/s : 0,003s

<em>/F/= 3900N</em>

*we use 0,003s as our time because the given time was 3ms.

*the final result is expressed in Newtons because our final result ends up beeing <em>kg.m/s²</em> = N

<u />

8 0
4 years ago
If you are asked to determine an object’s speed, what information must you have? A. distance and period of time B. distance and
Ierofanga [76]
<span>A. distance and period of time 
Hope this helps. c:</span>
6 0
3 years ago
Read 2 more answers
What happens to the velocity of an object when balanced forces act on it
mixas84 [53]
Nothing happens to velocity at all. Speed and direction remain constant.
6 0
3 years ago
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