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sashaice [31]
3 years ago
12

A curve has a radius of 50 meters and is banked 5 degrees. The road is covered with ice and is frictionless. What is the maximum

speed, in mph, a car can travel and negotiate the curve? A.) 15.65mph B.) 25.00mph C.)65.00mph D.) 6.55mph E.) None of the above
Physics
1 answer:
Salsk061 [2.6K]3 years ago
8 0

Answer:

E.) None of the above

Explanation:

Draw a free body diagram.  There are two forces acting on the car.  Normal force perpendicular to the road, and weight downward.

Sum of the forces perpendicular to the road:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

Sum of the forces towards the center of the circle:

∑F = ma

N sin θ = mv²/r

mg cos θ sin θ = mv²/r

g cos θ sin θ = v²/r

v = √(gr cos θ sin θ)

Given r = 50 m and θ = 5°:

v = √(9.8 m/s² × 50 m × cos 5° × sin 5°)

v = 6.52 m/s

v = 14.6 mph

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Well I don't know.  Let's actually LOOK at the picture and see if that helps.

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By golly, that means the length of <u><em>each</em></u> wave in  A  must be shorter than each wave in  B,  C,  or D.

The correct choice is <em> A </em>.  Looking at the picture did the trick !

7 0
3 years ago
An experimental tungsten light bulb filament has a length of 5 cm and a diameter of 0.074 cm. The filament is basically just a w
adell [148]

Answer:

power emitted is 1.75 W

Explanation:

given data

length l = 5 cm = 5 ×10^{-2} m

diameter d = 0.074 cm = 74 ×10^{-5} m

total filament emissivity = 0.300

temperature = 3068 K

to find out

power emitted

solution

we find first area that is π×d×L

area = π×d×L

area = π×74 ×10^{-5}×5 ×10^{-2}

area = 1162.3892  ×10^{-5} m²

so here power emitted  is express as

power emitted  = E × σ × area × (temperature)^4

put here all value

power emitted  = 0.300× 5.67 × 1162.3892  ×10^{-5}  × (3068)^4

power emitted = 1.75 W

5 0
3 years ago
Why does ice melt faster in water than in oil when both liquids are at the same temperature​
vekshin1
Water has a high specific heat capacity. Oil has a smaller heat capacity.
7 0
3 years ago
Read 2 more answers
7) Three resistors having resistances of 4.0 Ω, 6.0 Ω, and 10.0 Ω are connected in parallel. If the combination is connected in
viva [34]

Answer:

A, 0.59A

Explanation:

The total resistance in the circuit is the resistances in parallel plus that in series.

Total resistance for those in parallel is;

1/(1/4 +1/6 +1/10) = 1/ (15+10+6 /60)

1/(31/60)= 60/31 ohms

Hence total resistance of the circuit is;

60/31 + 2 = (60+62)/31 = 122/31=3.94 ohms

To calculate the current flowing through the 10ohm resistance we need to know the voltage drop by subtracting the voltage drop in the 2ohm resistance from the total voltage drop.

Voltage drop on the 2 ohm resistance is;

Current on the 2 ohm resistor × 2 ohms

V = I ×R ; I - current

R - resistance

Current drop on the 2ohm resistance is;

Total voltage in the circuit/ total resistance in the circuit

12/3.94= 3.05A

Voltage drop on the 2 ohm resistance;

3.05 × 2 = 6.10volts

Hence voltage drop on the parallel resistance would be ;

12-6.10= 5.90V

Now voltage drop in a parallel circuit is the same hence 5.90v is dropped in each of the parallel resistance.

That said, the current drop on the 10 ohm resistor would be;

5.90/10 = 0.59A

Remember V= I× R so that I = V/R

6 0
3 years ago
A bar magnet is dropped toward a conducting ring lying on the floor. As the magnet falls toward the ring, does it move as a free
REY [17]

Explanation:

According to the Faraday-Lenz law, a conductive ring generates an induced current due to the change in the magnetic flux caused by the motion of the bar magnet. This induced current generates a magnetic field opposite to the magnetic field of the bar, generating an upward force that opposes the weight of the bar magnet, Therefore, it does not move as a freely  falling object.

3 0
3 years ago
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