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2 years ago

Which of the following forms of radiation can penetrate up to a 2-cm layer of skin tissue?

Physics

2 answers:

Dmitry_Shevchenko [17]2 years ago

4 0

Answer:

d). X-rays

Explanation:

X -rays are also called photons. They are a packet of electro magnetic radiation. X rays originate from the shell of the electron. X rays are highly penetrating, and have a shorter wavelength than alpha particles and the beta particles. They are similar to the gamma rays which are also has a high penetrating power and easily pass through the human body.

Thus X rays can penetrate a skin tissue upto 2 cm thickness.

Paraphin [41]2 years ago

3 0

Answer:

Explanation:

Alpha and beta particles are actually particulate radiation. X and Gamma rays are electromagnetic radiation.

Among the options, beta particles and X-Rays are the ones that can penetrate skin, but only X-Rays can go 2 cm deeper.

Actually, beta particles or beta radiation in the tissue can penetrate just a few milimeters, but X-Rays can penetrate many centimeters. That's why X-Rays are used to examine bones, it's too deep to use beta radiation.

Therefore, the right answer is D.

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2 years ago

Consider a 20 cm thick granite wall with a thermal conductivity of 2.79 W/m·K. The temperature of the left surface is held const

kozerog [31]

Answer:

The right wall surface temperature and heat flux through the wall is 35.5°C and 202.3W/m²

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Temperature at the left side surface is T₁ = 50°C

Temperature of the air is T = 22°C

Convection heat transfer coefficient is h = 15 W/m2·K

Heat conduction process through wall is equal to the heat convection process so

$Q_{conduction} = Q_{convection}$

Expression for the heat conduction process is

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Expression for the heat convection process is

$Q_{convection} = h(T_2 - T)$

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$Q_{conduction} = Q_{convection}$

$\frac{K(T_1 - T_2)}{L} = h(T_2 - T)$

Substitute the values in above equation

$\frac{2.79(50- T_2)}{0.2} = 15(T_2 - 22)\\\\T_2 = 35.5^\circC$

Now heat flux through the wall can be calculated as

$q_{flux} = Q_{conduction} \\\\q_{flux} = \frac{K(T_1 - T_2)}{L}\\\\q_{flux} = \frac{2.79(50 - 35.5)}{0.2}\\\\q_{flux} = 202.3W/m^2$

Thus, the right wall surface temperature and heat flux through the wall is 35.5°C and 202.3W/m²

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Explanation:

hey

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Answer:

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