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RideAnS [48]
3 years ago
13

Which of the following forms of radiation can penetrate up to a 2-cm layer of skin tissue?

Physics
2 answers:
Dmitry_Shevchenko [17]3 years ago
4 0

Answer:

d). X-rays

Explanation:

X -rays are also called photons. They are a packet of electro magnetic radiation. X rays originate from the shell of the electron.  X rays are highly penetrating, and have a shorter wavelength than alpha particles and the beta particles. They are similar to the gamma rays which are also has a high penetrating power and easily pass through the human body.

 Thus X rays can penetrate a skin tissue upto 2 cm thickness.

Paraphin [41]3 years ago
3 0

Answer:

<h2>D. X-Rays</h2>

Explanation:

Alpha and beta particles are actually particulate radiation. X and Gamma rays are electromagnetic radiation.

Among the options, beta particles and X-Rays are the ones that can penetrate skin, but only X-Rays can go 2 cm deeper.

Actually, beta particles or beta radiation in the tissue can penetrate just a few milimeters, but X-Rays can penetrate many centimeters. That's why X-Rays are used to examine bones, it's too deep to use beta radiation.

Therefore, the right answer is D.

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What is the value of R2 in this parallel circuit? (5 stars)
o-na [289]

Answer:

20 Ω

Explanation:

Voltage, current, and resistance are related by Ohm's law:

V = IR

40 V = (4 A) R

R = 10 Ω

The total resistance of the circuit is 10 Ω.

Resistors in parallel have a total resistance of:

1/R = 1/R₁ + 1/R₂

1 / (10 Ω) = 1 / (20 Ω) + 1/R₂

R₂ = 20 Ω

4 0
2 years ago
How long will it take for a car to accelerate to come to a stop if it is traveling at 20m/s and the car has a maximum decelerati
Pachacha [2.7K]
When the car comes to a stop, the final velocity must be 0 m/s.
Since the car js decelerating in a forward direction, acceleration must be negative.

final v = initial v + a•t
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t = 3.33s
5 0
3 years ago
The total surface area of the human body is 1.20 m2 and the surface temperature is 30∘C=303∘K. If the surroundings are at a temp
zalisa [80]

To solve this problem we must consider the expressions of Stefan Boltzmann's law for which the rate of change of the radiation of energy H from a surface must be

H = Ae\sigma T^4

Where

A = Surface area

e = Emissivity that characterizes the emitting properties of the surface

\sigma = Universal constant called the Stefan-Boltzmann constant (5.67*10^{-8}m^{-2}K^{-4})

T = Absolute temperature

The total heat loss would be then

Q = H_2 -H_1

Q =Ae\sigma T_2^4-Ae\sigma T_1^4

Q = Ae\sigma (T_2^4-T_1^4)

Q = (1.2)(1)(5.67*10^{-8})(303^4-280^4)

Q = 155.29J

Therefore the net rate of heat loss from the body by radiation is 155.29J

8 0
3 years ago
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4 0
2 years ago
In the figure below (Figure 1), the upper ball is released from rest, collides with the stationary lower ball, and sticks to it.
Georgia [21]

(a) The frequency of the motion after the collision is 0.71 Hz.

(b) The maximum angular displacement of the motion after the collision is 16.3⁰.

<h3>Speed of the 2.2 kg ball when it collides with 2.7 kg ball</h3>

The speed of the 2.2 kg ball which was initially 10 cm higher that 2.7 kg ball is calculated as follows;

K.E = P.E

¹/₂mv² = mgh

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 0.1)

v = 1.4 m/s

<h3>Final speed of both balls after collision</h3>

The final speed of both balls after the collision is determined from the principle of conservation of linear momentum.

Pi = Pf

m₁v₁ + m₂v₂ = vf(m₁ + m₂)

2.2(1.4) + 2.7(0) = vf(2.2 + 2.7)

3.08 = 4.9vf

vf = 3.08/4.9

vf = 0.63 m/s

<h3>Maximum displacement of the balls after the collision</h3>

P.E = K.E

mgh_f = \frac{1}{2} mv_f^2\\\\h_f = \frac{v_f^2}{2g} \\\\h_f = \frac{(0.63)^2}{2(9.8)} \\\\h_f = 0.02 \ m

<h3>Maximum angular displacement</h3>

The maximum angular displacement of the balls after the collision is calculated as follows;

cos \theta = \frac{L - h_f}{L} \\\\cos\theta = \frac{0.5 - 0.02}{0.5} \\\\cos\theta = 0.96\\\\\theta = cos^{-1}(0.96)\\\\\theta = 16.3 \ ^0

<h3>Frequency of the motion</h3>

f = \frac{1}{2\pi} \sqrt{\frac{g}{L} } \\\\f = \frac{1}{2\pi } \sqrt{\frac{9.8}{0.5} } \\\\f = 0.71 \ Hz

Learn more about maximum angular displacement here: brainly.com/question/13665036

4 0
2 years ago
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