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RideAnS [48]
3 years ago
13

Which of the following forms of radiation can penetrate up to a 2-cm layer of skin tissue?

Physics
2 answers:
Dmitry_Shevchenko [17]3 years ago
4 0

Answer:

d). X-rays

Explanation:

X -rays are also called photons. They are a packet of electro magnetic radiation. X rays originate from the shell of the electron.  X rays are highly penetrating, and have a shorter wavelength than alpha particles and the beta particles. They are similar to the gamma rays which are also has a high penetrating power and easily pass through the human body.

 Thus X rays can penetrate a skin tissue upto 2 cm thickness.

Paraphin [41]3 years ago
3 0

Answer:

<h2>D. X-Rays</h2>

Explanation:

Alpha and beta particles are actually particulate radiation. X and Gamma rays are electromagnetic radiation.

Among the options, beta particles and X-Rays are the ones that can penetrate skin, but only X-Rays can go 2 cm deeper.

Actually, beta particles or beta radiation in the tissue can penetrate just a few milimeters, but X-Rays can penetrate many centimeters. That's why X-Rays are used to examine bones, it's too deep to use beta radiation.

Therefore, the right answer is D.

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5 0
3 years ago
Which event demonstrates electromagnetic waves transferring energy?
Citrus2011 [14]

Answer:

Sun heating a car sitting in a parking lot

Explanation:

The sun heating a car sitting in a parking lot is an example of electromagnetic waves transferring energy.

  • Electromagnetic waves are produced from the vibration between electric and magnetic fields.
  • These waves can be propagated through vacuum with no particles inside of them.
  • The sun produces electromagnetic radiation through the process of nuclear fusion.
  • These radiations are used to warm the earth surface.
  • The sun heating a car sitting a parking lot is one vivid example.
4 0
3 years ago
Read 2 more answers
An object is dropped from a platform 100 feet high. Ignoring wind resistance, what will its speed be when it reaches the ground?
ICE Princess25 [194]

<span>if we assume the origin is at the dropping point and the object is merely dropped and not thrown up or down then y0 = 0 and v0 = 0. The equation reduces to </span>

<span>y = 0 + 0t + ½gt² </span>
<span>y = ½gt² </span>

<span>t = √(2y/g) </span>

<span>in the ft - lb - s system </span>

<span>y = -100 ft </span>
<span>g = -32.2 ft / s² </span>

<span>t = √(2y/g) </span>
<span>t = √(2(-100) / (-32.2)) </span>
<span>t = 2.5 s</span>
7 0
3 years ago
Read 2 more answers
A projectile is launched at ground level with an initial speed of 54.5 m/s at an angle of 35.0° above the horizontal. It strikes
Alchen [17]
<h2>Answer: x=125m, y=48.308m</h2>

Explanation:

This situation is a good example of the projectile motion or parabolic motion, in which we have two components: x-component and y-component. Being their main equations to find the position as follows:

x-component:

x=V_{o}cos\theta t   (1)

Where:

V_{o}=54.5m/s is the projectile's initial speed

\theta=35\° is the angle

t=2.80s is the time since the projectile is launched until it strikes the target

x  is the final horizontal position of the projectile (the value we want to find)

y-component:

y=y_{o}+V_{o}sin\theta t-\frac{gt^{2}}{2}   (2)

Where:

y_{o}=0  is the initial height of the projectile (we are told it  was launched at ground level)

y  is the final height of the projectile (the value we want to find)

g=9.8m/s^{2}  is the acceleration due gravity

Having this clear, let's begin with x (1):

x=(54.5m/s)cos(35\°)(2.8s)   (3)

x=125m   (4)  This is the horizontal final position of the projectile

For y (2):

y=0+(54.5m/s)sin(35\°)(2.8s)-\frac{(9.8m/s^{2})(2.8s)^{2}}{2}   (5)

y=48.308m   (6)  This is the vertical final position of the projectile

4 0
3 years ago
Student swings a small rubber stopper attached to a string over her head in a horizontal, circular path. The string is 1.50 mete
harkovskaia [24]

Answer:

v = 18.84 m/s

Explanation:

Given that,

The length of the string, r = 1.5 m (it will act as radius)

The rubber stopper makes 120 complete circles every minute.

Since, 1 minute = 60 seconds

It means, its frequency is 2 circles every second.

Let we need to find the average speed of the rubber stopper. It can be calculated as follows :

v=\dfrac{d}{T}

d is distance, d=2\pi r and 1/T = f (frequency)

v=2\pi rf\\\\=2\pi \times 1.5\times 2\\\\=18.84\ m/s

So, the average speed of the rubber stopper is 18.84 m/s.  

4 0
3 years ago
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