Why are noble metals for example Rhodium, Palladium, Platinum, and Iridium largely used in chemical manufacturing as heterogeneo
1 answer:
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Answer: 0.100 m
Explanation:
Elevation in boiling point is given by:
= Elevation in boiling point
i= vant hoff factor
= boiling point constant
m= molality
1. For 0.100 m
, i= 3 as it is a electrolyte and dissociate to give 3 ions. and concentration of ions will be
2. For 0.100 m
, i= 2 as it is a electrolyte and dissociate to give 2 ions, concentration of ions will be
3. For 0.200 m
, i= 1 as it is a non electrolyte and does not dissociate, concentration of ions will be
4. For 0.060 m
, i= 4 as it is a electrolyte and dissociate to give 4 ions. and concentration of ions will be
Thus as concentration of solute is highest for , the elevation in boiling point is highest and thus has the highest boiling point.
Answer:
1, 2, and 3 are true.
Explanation:
The Henderson-Hasselbalch equation is:
pH = pka + log₁₀
- If the pH of the solution is known as is the pKa for the acid, the ratio of conjugate base to acid can be determined. <em>TRUE</em>
pH = pka + log₁₀
If you know pH and pka:
10^(pH-pka) =
The ratio will be: 10^(pH-pka)
- At pH = pKa for an acid, [conjugate base] = [acid] in solution. <em>TRUE</em>
pH = pka + log₁₀
0 = log₁₀
10^0 =
1 =
As ratio is 1, [conjugate base] = [acid] in solution.
- At pH >> pKa for an acid, the acid will be mostly ionized. <em>TRUE</em>
pH = pka + log₁₀
If pH >> pKa, 10^(pH-pka) will be >> 1, that means that you have more [A⁻] than [HA]
- At pH << pKa for an acid, the acid will be mostly ionized. <em>FALSE</em>
pH = pka + log₁₀
If pH << pKa, 10^(pH-pka) will be << 1, that means that you have more [HA] than [A⁻]
I hope it helps!