Answer:
98.12 m
Explanation:
Initial speed(v) = 25.0 m/s
Coefficient of static friction (u) = 0.650
The minimum value of the coefficient of kinetic friction should be the coefficient of static friction.
Kinetic friction is given as
umg = ma (a is the required acceleration)
We then have
a = -ug
= -(0.65*9.8)
= -6.37 m/s^2
The shortest distance d is obtained by
d = (V^2 - v^2)/ 2a
V = 0 m/s (final velocity)
d = (0 - 25^2) / 2(-6.37)
d = -625/-6.37
d = 98.12 m
I don't really know but I don't think you can... I can't explain it either. Sorry im no help
Answer:
Force = 100N
Explanation:
Force = mass × acceleration
Answer:
Momentum = 1.534 kgm/s
Explanation:
Using the equations of motion, we can obtain the velocity of the ball as it hits the ground.
g = 9.8 m/s²
y = 12 m
u = initial velocity = 0 m/s, since the ball was released from rest
v = final velocity befor the ball hits the ground.
v² = u² + 2ay
v² = 0 + 2×9.8×12 = 235.2
v = 15.34 m/s
The momentum at any point is given as mass × velocity at that point
Mass = 100 g = 0.1 kg, velocity = 15.34 m/s
Momentum = 0.1 × 15.34 = 1.534 kgm/s
