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1 year ago

When you changed from low to high power, how did the change affect the working distance of the lens?

1 answer:

4 0

The working distance gets shorter as the magnification gets bigger. In order to focus, the high-power objective lens must be significantly nearer to the specimen than the low-power lens. Magnification is negatively correlated with working distance.

Magnification change The magnification of a specimen is increased by switching from low power to high power. The magnification of an image is determined by multiplying the magnification of the objective lens by the magnification of the ocular lens, or eyepiece.

The geometry of the optical system connects the magnifying power, or how much the thing being observed seems expanded, and the field of view, or the size of the object that can be seen.

To know more about working distance

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A truck with 0.410 m radius tires travels at 25.0 m/s. What is the angular velocity of the rotating tires in radians per second?

Eduardwww [97]

relation between linear velocity and angular velocity is given as

$v = R\omega$

here

v = linear speed

R = radius

$\omega$ = angular speed

now plug in all data in the equation

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so rotating speed is 60.9 rad/s

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Equal force is applied to a baseball, a basketball, a tennis ball, and a bowling ball. Which ball will have the GREATEST acceler

mr_godi [17]

according to newton's second law , net force on an object is equal to the product of its mass and its acceleration. the formula is given as

F = ma

where F = force , m = mass , a = acceleration

rearranging the equation for acceleration "a" , we get

a = F/m

when force F is kept constant , the acceleration is inversely related to the mass "m". in other words, greater the mass , smaller will be the acceleration and smaller the mass, greater will be the acceleration.

the masses of baseball, basketball, tennis ball and bowling ball can in arranged in increasing order as

tennis ball < baseball < basketball < bowling ball.

since acceleration and mass have inverse relation from the formula , the order of the acceleration will also be reverse.

tennis ball > baseball > basketball > bowling ball.

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3 years ago

Calculate the force of gravity on a 1–kilogram box located at a point 1.3 × 107 meters from the center of Earth if the force on

Sati [7]

Since you already gave us the weight of the 2.5-kg box,
we don't even need to know what the distance is, just
as long as it doesn't change.

Look at the formula for the gravitational force:

F = G m₁ m₂ / R² .

If 'G', 'm₁' (mass of the Earth), and 'R' (distance from the Earth's center)
don't change, then the Force is proportional to m₂ ... mass of the box,
and you can write a simple proportion:

(6.1 N) / (2.5 kg) = (F) / (1 kg)

Cross-multiply: (6.1 N) (1 kg) = (F) (2.5 kg)

Divide each side by (2.5 kg): F = (6.1N) x (1 kg) / (2.5 kg) = 2.44 N .

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3 years ago

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Greeley [361]

You would use distance an time formula to mathmaticly solve

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