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Ivenika [448]
3 years ago
8

if you could count individual atoms at the rate of one per second, about how many years would be required to count 6.02x10^23 at

oms?
Chemistry
1 answer:
Arte-miy333 [17]3 years ago
3 0
Roughly 19,089,294,774,226,281 years
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How could you determine whether one of these two suspected compounds was identical to the unknown compound without using any for
sukhopar [10]

Answer: Use Mixture Melting Point

Explanation:

A procedure called mixture melting point would be used to determine whether or not the suspected compound is identical to the unknown.

The two suspected compounds would need to be used to create a new mixture and determine the mixtures melting point. Compare this melting points with that of the unknown compound in order to determine which one of these two suspected compounds is identical to the unknown compound.

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3 years ago
Determine the equilibrium constant, Keq, at 25°C for the reaction
adelina 88 [10]

Explanation:

The given chemical reaction is:

2Br^- (aq) + I_2(s)  Br_2(l) + 2I^- (aq)

E^ocell=oxidation potential of anode + reduction potential of cathode\\

The relation between Eo cell and Keq is shown below:

deltaG=-RTlnK_e_q\\delta=-nFE^o cell\\=>nFE^o cell=RTlnK_e_q\\lnK_e_q=\frac{nF}{RT} E^o cell

The value of Eo cell is:

Br- undergoes oxidation and I2 undergoes reduction.

Reduction takes place at cathode.

Oxidation takes place at anode.

Hence,

E^ocell= (-1.07+0.53)V\\=-0.54V

F=96485 C/mol

n=2 mol

R=8.314 J.K-1.mol-1

T=298K

Substitute all these values in the above formula:

ln K_e_q=\frac{2mol* 96485 C/mol}{8.314 J.K^-^1.mol^-^1x298K} \\\\lnK_e_q=77.8\\K_e_q=e^7^7^.^8\\=>K_e_q=6.13x10^3^3

Answer:

Keq=6.13x10^33

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3 years ago
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Which statement describes an Arrhenius acid
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According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs. Hence, the correct statement is arrhenius acid produces hydrogen ions in solution.

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3 years ago
There are two naturally occurring isotopes of indium: indium-113 and indium-115. How many neutrons are in a single atom of indiu
KonstantinChe [14]
There are 66 neutrons in a single atom of indium-115. The atomic number of indium-115 is 49, meaning there are 49 protons. Then the atomic mass is 115, so 115-49 = 66. 
5 0
3 years ago
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