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kompoz [17]
3 years ago
14

Given the unbalanced ionic equation:

Chemistry
2 answers:
oee [108]3 years ago
6 0
The answer is (2) 2, because a total of 6 electrons is transferred. We can know the electron transferred number form Mg to Mg2+ ion. There is 3 Mg involved and two electrons per atom. So total is 6,
ivolga24 [154]3 years ago
4 0

<u>Answer:</u> The correct answer is Option 2.

<u>Explanation:</u>

For the given redox reaction, magnesium is getting oxidized because it is loosing electrons and iron is getting reduced because it is gaining electrons.

The half reaction for oxidation and reduction is given by the equations:

Oxidation half reaction:  Mg\rightarrow Mg^{2+}+2e^-       ×  3

Reduction half reaction:  Fe^{3+}+3e^-\rightarrow Fe      ×  2

Net ionic reaction: 3Mg+2Fe^{3+}\rightarrow 3Mg^{2+}+3Fe

Total number of electrons transferred are 6.

So, the correct answer is Option 2.

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Convert the density 2.32 g/mL to the unit kg/m3.
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8 0
3 years ago
Which element has the largest atomic radii in the 3rd period of the periodic table?
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3 0
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How many moles are in 75.0 grams of nitrogen gas, N2?
Westkost [7]

<u>Given:</u><u>                                                                                                                       </u>

Mass of Nitrogen (N₂) gas = 75 grams

<u>Finding the number of moles of N₂:</u><u>                                                                     </u>

We know that the molar mass of N₂ is 28 grams/mole

Number of moles = Given mass / Molar mass

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Hence, there are 2.68 moles in 75 grams of Nitrogen Gas

7 0
3 years ago
Differentiate between strong and weak acid ​
Free_Kalibri [48]

Answer:

Acid solutions contain hydrogen ions. The higher the concentration of hydrogen ions, the lower the pH.  Strong acids are fully ionised but weak acids are only partly ionised in solution.

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6 0
3 years ago
A 1.638 Gram pure sample of a compound containing only carbon hydrogen and oxygen was burned in excess oxygen gas 3.117 g of car
andrew11 [14]

Answer:

C2H6O

Explanation:

<u>First, find the masses of C, H, and O. I used ratios.</u>

3.117g CO2  x  1 mol CO2/44.01g CO2  x  1 mol C/1 mol CO2  x  12.01g C/1 mol C = 0.850606 g C

1.911g H2O  x  1 mol H2O/18.016g H2O  x  2 mol H2O/1 mol H2O  x  1.008g H/1 mol H = 0.213842 g H

To find the mass of oxygen, just add the masses of C and H together and subtract that from the total mass of the sample.

1.638 - (0.850606 + 0.213842) = 0.57355 g O

<u>Second, find the moles of C, H, and O.</u>

0.850606g C  x  1 mol C/12.01g C = 0.070825 mol C

0.213842g H  x  1 mol H/1.008g H = 0.212145 mol H

0.57355 g O  x  1 mol O/16g O = 0.035847 mol O

<u>Finally, divide the number of moles of each element by the smallest value of moles calculated. In this case, the smallest value is 0.035847.</u>

0.070825/0.035847 = 2

0.212145/0.035847 = 6

0.035847/0.035847 = 1

7 0
3 years ago
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