All categories

4 years ago

Which travels along a surface separating two media?

Physics

2 answers:

xeze [42]4 years ago

8 0

surface waves are the wave that travel long a surface separating two media

Tom [10]4 years ago

5 0

I think it would be answer B. a surface wave

You might be interested in

A Ferris wheel with radius 14.0 m is turning about a horizontal axis through its center. The linear speed of a passenger on the

Marina86 [1]

Answer:

a) The acceleration experimented by the passenger when she passes through the lowest point of her circular motion is: $a_{R} = 2.571\,\frac{m}{s^{2}}$ , $\angle = 90^{\circ}$ .

b) Hence, the acceleration experimented by the passenger when she passes through the highest point of her circular motion is: $a_{R} = 2.571\,\frac{m}{s^{2}}$ , $\angle = 270^{\circ}$ .

c) The Ferris wheel takes 14.646 seconds to make a revolution.

Explanation:

a) An object that rotates at constant angular velocity reports a centripetal acceleration and no tangential acceleration. When passenger passes through the lowest point in her circular motion, centripetal acceleration goes up to the center.

In addition, centripetal acceleration is determined by the following expression:

$a_{R} = \frac{v^{2}}{R}$ (Eq. 1)

Where:

$a_{R}$ - Centripetal acceleration, measured in meters per square second.

$v$ - Linear speed, measured in meters per second.

$R$ - Radius of the Ferris wheel, measured in meters.

If we know that $v = 6\,\frac{m}{s}$ and $R = 14\,m$ , the magnitude of radial acceleration is:

$a_{R} = \frac{\left(6\,\frac{m}{s} \right)^{2}}{14\,m}$

$a_{R} = 2.571\,\frac{m}{s^{2}}$

The acceleration experimented by the passenger when she passes through the lowest point of her circular motion is: $a_{R} = 2.571\,\frac{m}{s^{2}}$ , $\angle = 90^{\circ}$ .

b) In the highest point the magnitude of radial acceleration is the same but direction is the opposed to that at lowest point. That is, centripetal acceleration goes down to the center.

Hence, the acceleration experimented by the passenger when she passes through the highest point of her circular motion is: $a_{R} = 2.571\,\frac{m}{s^{2}}$ , $\angle = 270^{\circ}$ .

c) At first we need to calculate the angular velocity of the Ferris wheel ( $\omega$ ), measured in radians per second, by using the following expression:

$\omega = \frac{v}{R}$ (Eq. 2)

If we know that $v = 6\,\frac{m}{s}$ and $R = 14\,m$ , then the angular velocity of the Ferris wheel is:

$\omega = \frac{6\,\frac{m}{s} }{14\,m}$

$\omega = 0.429\,\frac{rad}{s}$

Now we proceed to obtain the period of the Ferris wheel ( $T$ ), measured in seconds, which is the time needed by that wheel to make on revolution:

$T = \frac{2\pi}{\omega}$ (Eq. 3)

Where $\omega$ is the angular velocity of the Ferris wheel, measured in radians per second.

If we get that $\omega = 0.429\,\frac{rad}{s}$ , then:

$T = \frac{2\pi}{0.429\,\frac{rad}{s} }$

$T = 14.646\,s$

The Ferris wheel takes 14.646 seconds to make a revolution.

8 0

3 years ago

What can you conclude about this product?

aksik [14]

What’s the question

6 0

4 years ago

The energy gained by electrons as they are accelerated by an electric field is

Ilia_Sergeevich [38]

The energy gained by an electron as it is accelerated by an electric field is equal to the work done by the electric field itself, and this is equal to the product between the charge of the electron and the potential difference across which the electron traveled:
$\Delta U = W = e \Delta V$ (1)
where e is the electron charge, and $\Delta V$ is the potential difference between the initial and the final point of the electron, and this is equal to
$\Delta V = Ed$ (2)
where E is the intensity of the electric field and d is the distance covered by the electron. If we substitute (2) into (1), we find a final expression for the energy gained by the electron
$\Delta U = e E d$

6 0

3 years ago

A population of birds walks along the shores of a swampy area eating small crabs. Climatic changes cause the water level in the

sergejj [24]

R there any answer choices

4 0

4 years ago

An engine has an imput of 100 j and gives out 27 j of useful kenetic energy what is the efficiency of the engine

Lunna [17]

Answer:

Based on what we have learned so far, in what ways have the experiences of Asian-Canadians stayed the same over time? Why do you think these similarities exist? Please give specific examples to support your ideas.

Explanation:

4 0

3 years ago