For a merry go round with a radius of R=1.8 m and moment of inertia I=184 kg-m^2 is spinning with an initial angular speed of w=1.48 rad/s is mathematically given as
F= 618.9 N
<h3>What is the centripetal
force?</h3>
Generally, the equation for the angular speed is mathematically given as
w = v/R
Therefore
w= 4.7/1.8
w= 2.611 rad/s
Where total momentum
Tm= 642.96 + 272.32
Tm= 915.28
and total inertia
Ti= 184 + 246.24
Ti= 430.24
In conclusion, centripetal force
F= mrw^2
F = m*R*w2^2
F = 76*1.8*2.127^2
F= 618.9 N
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a merry go round with a radius of R=1.8 m and moment of inertia I=184 kg-m^2 is spinning with an initial angular speed of w=1.48 rad/s in the counter clockwise direction when viewed from above a person with mass m=76 kg and velocity v=4.7 m/s runs on a path tangent to the merry go round once at the merry go round the person jumps on and holds on to the rim of the merry go round angular speed of the merry go round after the person jumps on 2.127 rad/s Once the merry go round travels at this new angular speed with what force does the person need to hold on?
By Considering the vertical distance and both vertical and horizontal final velocity, the time t = 0.45 s and Velocity V = 6.7 m/s
Given that a Veggie meatball with v = 5.0 m/s rolls off a 1.0 m high table.
Height h = 1.0 m
As the ball rolls off the table, it will be fallen under gravity. Where
g = 9.8 m/
Initial vertical velocity 
= 0
Initial horizontal velocity 
= 5 m/s
Considering the vertical distance, the formula to use to calculate the time will be;
h = ut + 1/2g
1 = 0 + 1/2 x 9.8
1 = 4.9
= 1/4.9
t = 
t = 0.45 seconds
It takes 0.45 seconds to hit the floor if no one sneezes.
To calculate its velocity when it hits the floor, we will need to calculate for both vertical and horizontal final velocity and find the resultant velocity of the two.
Vertical component
= 
+ gt
= 0 + 9.8(0.45)
= 4.41 m/s
Horizontal component
= + at
but a = 0
= 5 m/s
Final velocity V = 
V = 6.67 m/s
Therefore, it will hit the floor at a velocity of 6.7 m/s
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Answer:
c. 981 watts
Explanation:
Given:
- horizontal speed of treadmill,
- weight carried,
- grade of the treadmill,
<u>Now the power can be given by:</u>
(where grade is the rise of the front edge per 100 m of the horizontal length)
Answer:
Canada moves south
Explanation:
In North America, winter storms usually form when an air mass of cold, dry, Canadian air moves south and interacts with a warm, moist air mass moving north from the Gulf of Mexico at a point called Front.
Answer:E
=
252
J
Explanation:
The total mechanical energy of an object or system is given by:
E
m
e
c
h
=
K
+
U
Where
K
is the kinetic energy of the object and
U
is the potential energy of the object. The carriage, sitting motionless at the top of the hill, has only potential energy in the form of gravitational potential energy.
Gravitational potential energy is given by:
U
g
=
m
g
h
Where
m
is the mass of the object,
g
is the gravitational acceleration constant, and
h
is the height of the object above some specific reference point, in this case the ground
21
m
below.
The weight of a stationary object at the surface of the earth is equal to the force of gravity acting on the object.
W
=
→
F
g
=
m
g
We are given that the carriage weighs
12
N
, therefore
m
g
=
12
N
.
U
g
=
12
N
⋅
21
m
⇒
U
g
=
252
N
m
=
252
J
Answer link
Explanation:
