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Andreyy89
3 years ago
12

Why are triangles important when making structures

Physics
1 answer:
Alex_Xolod [135]3 years ago
4 0
So when making structures you have to have squares rectangles right and a triangle and another triangle equals a square so thats all there is to it
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A small metal sphere weighs 0.34 N in air and has a volume of 13 cm3 . What is the acceleration of the sphere as it falls throug
Xelga [282]

To solve this problem we will apply the concepts related to the balance of forces. Said balance will be given between buoyancy force and weight, both described as derived from Newton's second law, are given as

Buoyancy force

F_B = V\rho g

Here,

V = Volume

\rho=Density of air

g = Acceleration due to gravity

Weight

F_W = mg

m = mass

g = Gravity

Our values are given as,

\text{Weight of the sphere} = W = 0.34 N

\text{Volume} = V = 13 cm^3 = 13*10^{-6}m^3

\text{density of air} =\rho =1.29kg/m^3

\text{gravity}= g = 9.8 m/s^2

Then,

F = V\rho g

Replacing,

F = (13*10^{-6}m^3 )(1.29Kg/m^3)( 9.8 m/s^2) = 1.6434* 10^{-4} N

Now net force is ,

F_{net} = mg - F

Mass of the sphere is

m = \frac{W}{g} = \frac{0.34N}{9.8m/s^2} = 0.03469 kg

Now acceleration of the sphere is

a = \frac{F_{net}}{m}

a = \frac{( 0.34 N)- (1.6434* 10^{-4} N)}{0.03469 kg}

a = 9.822m/s^2

Therefore the acceleration of the sphere as it falls through water is 9.822m/s^2

5 0
3 years ago
Two speakers are spaced 15 m apart and are both producing an identical sound wave. You are standing at a spot as pictured. What
IgorLugansk [536]

Answer:

Frequency is 213.04\ s^{-1}.

Explanation:

Distance between source 1 from the receiver , S_1 =\sqrt{10^2+22^2}=24.17\ m.

Distance between source 2 from the receiver , S_2=\sqrt{5^2+22^2}=22.56\ m.

Now ,

Path difference , r = S_1-S_2=24.17-22.56=1.61\ m.

We know, for constructive interference path difference should be integral multiple of wavelength .  

Therefore, r=n\times \lambda

It is given that n = 1,

Therefore, \lambda=1.61\ m.

Frequency can be found by , \nu=\dfrac{v}{\lambda}= \dfrac{343}{1.61}=   213.04\ s^{-1} .

Hence, this is the required solution.

5 0
3 years ago
A 8kg cat us running 4 m/s. How much kenetic energy is that
Flauer [41]
     Using the Definition of Kinetic Energy, we have:

E_{c}= \frac{mv^2}{2}  \\ E_{c}= \frac{8*4^2}{2}  \\ \boxed {E_{c}=64J}
3 0
3 years ago
A 2.0-kg block is on a perfectly smooth (frictionless) ramp that makes an angle of 30^\circ30 ​∘ ​​ with the horizontal. What is
Nastasia [14]

Answer:

Explanation:

Since the surface is frictionless therefore there will be no friction force on block but there will be weight of block which we can divide in to two components i.e. mgcosθ &mgsinθ which is perpendicular and parallel to the surface respectively.

In response to mgcosθ ramp will apply a normal force to the block which will be of equal magnitude to that of mgcosθ.

Therefore Ramp will apply a Force of mgcosθ on block where m is the mass of block.

7 0
3 years ago
What is the main reason why many nuclear power plants are located near bodies of water?
PilotLPTM [1.2K]
The answer is C but man if you have leak or a meltdown good luck to anyone downstream.

6 0
3 years ago
Read 2 more answers
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