Answer: 9.9%
Explanation: efficiency = (work output /work input) × 100
Note that, 1 kilocalorie = 4184 joules, hence 22kcal = 22× 4184 = 92048 joules.
Work output = 9200 j and work input = 92048 j
Efficiency = (9200/92048) × 100 = 0.099 × 100 = 9.9%
Answer:
I think option A is correct
=> it increases the initial energy of the reactants
hope it helps
Yes, a test could be performed to support the claim.
Hypothesis: The claim that a manufacturer’s cleanser works
twice as fast as any other cleanser.
So, based from this hypothesis, we can perform the following
tests:
We assign Cleanser A to the manufacturer that claims that their cleanser works
twice as fast as any other cleanser and Cleanser B to the cleanser to be
compared with.
1.
Get two tiles and put the same amount of stain
on them.
2.
Apply Cleanser A on the first tile and Cleanser
B on the second tile.
3.
Apply the same amount of force in removing the
stains on both tiles
4.
Record the amount of time it takes to remove the
stains on each tile.
<span>Self-monitoring would be the best way to </span><span>determine your own correct intensity level. I hope this helps! <3
</span>
The "weight" is the name we give to the force of gravity on the object. They're the same thing.
