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earnstyle [38]
2 years ago
14

The vertical component of the acceleration of a sailplane is zero when the air pushes up against its wings with a lift force of

5.20 kN. Assume that the only forces on the sailplane are that due to gravity and that due to the air pushing up against its wings. What will be the gravitational force on Earth due to the sailplane
Physics
1 answer:
lorasvet [3.4K]2 years ago
3 0

Answer:

Explanation:

The vertical component of the acceleration of a sailplane is zero , that means the sailplane is experiencing net force of zero in vertical direction . Its weight is acting in downward direction . So airplane is also experiencing an upward force equal to its weight  which is making net force equal to zero on it . This force is given as 5.20 k N .

So sailplane is experiencing an upward force equal to its weight . This force is generated due to air pushing up against its wings .

We know that every force generated has equal and opposite reaction force . Air is generating force on wings of sailplane , hence wings will also exert equal force on air on downward direction . This force will be transmitted to the earth by air .

Hence the gravitational force on Earth due to the sailplane will be equal to weight of sailplane . This force is 5.2 kN .

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The heat capacity of nickel is 0.444 J/(g · °C). Calculate the amount of heat needed to raise the temperature of 18 g of nickel
azamat

The final speed of the nickel at the given quantity of heat is determined as 202.1  m/s.

<h3>Final speed of the nickel</h3>

Apply the principle of conservation of energy.

Q = mcΔθ

Q = (18)(0.444)(66 - 20)

Q = 367.63 J

Q = K.E = ¹/₂mv²

2K.E = mv²

v = √(2K.E/m)

where;

  • v is the final speed

v = √(2 x 367.63)/(0.018))

v = 202.1 m/s

Learn more about speed here: brainly.com/question/4931057

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6 0
2 years ago
Read 2 more answers
A train at a constant 60.0 km/h moves east for 40.0 min, then in a direction 50.0 degrees east of due north for 20.0 min, and th
son4ous [18]

Answer:

Part a)

v = 7.57 km/h

Part b)

\theta = 67.5 degreeNorth of East

Explanation:

Speed of train towards East = 60 km/h

displacement towards East is given as

d_1 = 40 km

now it turns towards 50 degree East of North

so its distance is given as

d_2 = 20 km(sin50 \hat i + cos50\hat j)

d_2 = 15.3 \hat i + 12.8 \hat j

then finally it moves towards west for 50 min

d_3 = -50 \hat i

Now the total displacement of the train is given as

d = d_1 + d_2 + d_3

d = (40 + 15.3 - 50)\hat i + 12.8 \hat j

d = 5.3\hat i + 12.8 \hat j

now total time duration of the motion is given as

T = 40 min + 20 min + 50 min

T = 1.83 h

now average velocity is given as

v_{avg} = \frac{5.3\hat i + 12.8\hat j}{1.83}

v_{avg} = 2.89\hat i + 6.99\hat j

Part a)

magnitude of the average velocity is given as

v = \sqrt{v_x^2 + v_y^2}

v = \sqrt{2.89^2 + 6.99^2}

v = 7.57 km/h

Part b)

Direction of the velocity is given as

tan\theta = \frac{v_y}{v_x}

tan\theta = \frac{6.99}{2.89}

\theta = 67.5 degreeNorth of East

6 0
3 years ago
How long will it take a car to travel a distance of 1km if it has an average speed of 60kph​
beks73 [17]

Answer:

1÷60 h

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6 0
3 years ago
If Bert the Bat travels East at 200 meters in 10 seconds, what is his velocity?
dexar [7]

Answer:

20m/s due east

Explanation:

Given parameters:

Displacement eastward  = 200m

Time  = 10s

Unknown:

Velocity  = ?

Solution:

Velocity is the displacement divided by time;

    Velocity  = \frac{displacement}{time}  

 Velocity  = \frac{200}{10}    = 20m/s due east

4 0
3 years ago
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