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Olenka [21]
4 years ago
14

The magnitude of the force associated with the gravitational field is constant and has a value F. A particle is launched from po

int B with an initial velocity and reaches point A having gained U0 joules of kinetic energy. A resistive force field is now set up such that it is directed opposite the gravitational field with a force of constant magnitude 12F. A particle is again launched from point B. How much kinetic energy will the particle gain as it moves from point B to point A
Physics
1 answer:
Goryan [66]4 years ago
4 0

Answer:

Energy gained by the second particle = 12Uo

Explanation:

Given Data;

Resistant force = 12F

Initial kinetic energy = Uo

Calculating the kinetic energy gained, we have;

u = f *r

where f= resistant force = 20F

r = initial kinetic energy = Uo

Therefore,

U = 12 * uo

  = 12 Uo

Therefore, energy gained by the second particle = 12Uo

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A motorcycle is following a car that is traveling at a constant speed on a straight highway. Initially, the car and the motorcyc
Artist 52 [7]

Answer:

(a) 3.807 s

(b) 145.581 m

Explanation:

Let Δt = t2 - t1 be the time it takes from the moment when the motorcycle starts to accelerate until it catches up with the car. We know that before the acceleration, both vehicles are travelling at a constant speed. So they would maintain a distance of 58 m prior to the acceleration.

The distance traveled by car after Δt (seconds) at v_c = 23m/s speed is

s_c = \Delta t v_c = 23\Delta t

The distance traveled by the motorcycle after Δt (seconds) at m_m = 23 m/s speed and acceleration of a = 8 m/s2 is

s_m = \Delta t v_m + a\Delta t^2/2

s_m = 23\Delta t + 8\Delta t^2/2 = 23 \Delta t + 4 \Delta t^2

We know that the motorcycle catches up to the car after Δt, so it must have covered the distance that the car travels, plus their initial distance:

s_m = s_c + 58

23 \Delta t + 4 \Delta t^2 = 23\Delta t + 58

4 \Delta t^2 = 58

\Delta t^2 = 14.5

\Delta t = \sqrt{14.5} = 3.807s

(b)

s_m = 23 \Delta t + 4 \Delta t^2

s_m = 23*3.807 + 58 = 145.581 m

5 0
3 years ago
A car travels at a constant rate for 100 miles going due west for one hour. Then it travels at a constant rate for another 75 mi
nirvana33 [79]

Answer:

C. 100 mph west

Explanation:

Average velocity is total displacement over total time.  During the first hour, the average velocity is:

v_avg = 100 mi / 1 hr

v_avg = 100 mph west

Since the velocity is constant, the instantaneous velocity at any time equals the average velocity.

v = v_avg

v = 100 mph west

7 0
4 years ago
A solid cylinder (1 =1/2mr2 ) with a mass of 4.83 kg and a radius of 0.057 m starts
netineya [11]

Answer:

v = 7.32 m/s

Explanation:

The potential energy will convert to kinetic energy

        ½Iω² + ½mv² = mgh

             Iω² +  mv² = 2mgh

(½mR²)(v/R)² + mv² = 2mgh

           ½mv² + mv² = 2mgh

                 ½v² + v² = 2gh

                      3v²/2 = 2gh

                           v² = 4gh/3

                           v² = 4(9.81)(4.10)/3

                           v² = 53.628

                            v = 7.323114...

                            v = 7.32 m/s

3 0
3 years ago
What was one result of the second great awakening
Brrunno [24]
The membership rose among the baptist and methodists.
4 0
4 years ago
The Force Of Gravity Acting On A Childs Mass On Earth Is 490 newtons whats the childs mass
Flauer [41]
Force of gravity on an object is the weight of the object and is given by mass times accerelation due to gravity. The accerelation due to gravity is the accerelation of an object in free fall and is given by 9.8m/s^2. Given that the force of gravity acting on a child's mass on earth is 490 newtns, i.e. F = mg which means that 490 newtons = 9.8 times mass. Therefore, mass of the child is 490 / 9.8 = 50 kg.
3 0
4 years ago
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