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hjlf
3 years ago
5

Consider the reaction of zinc sulfide and oxygen:

Chemistry
1 answer:
Svetach [21]3 years ago
8 0

Answer:

Mass = 0.004 g

Explanation:

Given data:

Mass of zinc sulfide = 46.32 g

Mass of oxygen = 15.5172 g

Mass of zinc oxide = ?

Solution:

Chemical equation:

2ZnS + 3O₂ → 2ZnO + 2SO₂

Number of moles of ZnS:

<em>Number of moles = mass/ molar mass</em>

Number of moles =  46.32 g/ 97.5 g/mol

Number of moles = 0.46 mol

Number of moles of Oxygen:

<em>Number of moles = mass/ molar mass</em>

Number of moles =  15.5172 g/ 32 g/mol

Number of moles = 0.48 mol

Now we will compare the moles of oxygen and zinc sulfide with zinc oxide.

                            ZnS        :       ZnO

                               2          :          2

                             0.46       :         0.46

                             O₂          :          ZnO

                             3            :            2

                             0.48       :           2/3×0.48 =0.32 mol

The number of moles of zinc oxide produced by oxygen are less so it will limiting reactant.

Mass of zinc oxide:

Mass = number of moles / molar mass

Mass = 0.32 mol / 81.38 g/mol

Mass = 0.004 g

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