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8_murik_8 [283]
3 years ago
6

A man releases a stone ar the top edge of a tower during the last second of its travel the stone falls through a distance of (9/

25)H where H is the towes highr. Find H
Physics
2 answers:
Lapatulllka [165]3 years ago
7 0

equations of motion (EoM) use EoM <span><span>v2</span>=<span>u2</span>+2ax</span> to establish velocities at positions shown in blue in drawing from EoM <span>v=u+at</span> for final 1 second of flight time, we can say <span>v=u+g(1)</span> <span><span><span>2gH</span><span>−−−−</span>√</span>=<span><span>2g<span>1625</span>H</span><span>−−−−−−</span>√</span>+g</span><span> then, solve for H [in terms of g]</span>
Musya8 [376]3 years ago
4 0
Equations of motion (EoM) use EoM <span>v2=u2+2ax</span> to establish velocities at positions shown in blue in drawing from EoM v=u+at for final 1 second of flight time, we can say v=u+g(1) <span><span>2gH−−−−√</span>=<span><span>2g1625H</span>−−−−−−√</span>+g</span><span> then, solve for H [in terms of g]

</span>
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Answer:

3400 Hz

Explanation:

We know that

1 cm = 0.01 m

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The human ear canal behaves as a closed pipe and for a closed pipe, nth resonant frequency is given as

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Inserting the values

f = \frac{(2(1) - 1) 340}{4(0.025)}

f = \frac{340}{4(0.025)}

f = 3400 Hz

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