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Marina86 [1]
2 years ago
9

How is the L-section filter useful at both low and high frequencies?​

Physics
2 answers:
Gnom [1K]2 years ago
8 0

Answer: High pass filters, and in particular LC high pass filters are used in many RF applications where they block the lower frequencies and allow through higher frequency signals. Typically LC filters are used for the higher radio frequencies where active filters are not so manageable, and inductors more appropriate.

Lerok [7]2 years ago
5 0

Answer:

high pass filters and in particular LC high pass filter are used in many RF application where they block the lower frequencies and allow through higher frequency signals. Typically LC filters are used for the higher radio frequencies where active filters are not so manageable and indicators more appropriate

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yaroslaw [1]

The AREA of the shaded region is the moving object's displacement.

7 0
3 years ago
Expain how a hurricane develops
Firlakuza [10]

Answer:

A hurricane starts to form when warm air rises and then that warm air turns into cooler air. After a while of this happening large clouds and thunderstorms    are made. The clouds and thunderstorms keep growing and rotating from earth's Coriolis Effect. Then a hurricane forms.

6 0
2 years ago
Un automóvil acelera de 0 a 140 km/h en 9.8 segundos, determina su aceleración
guajiro [1.7K]

Answer:

The acceleration is 14.28 km/h^2

Explanation:

Step one:

Given data

initial speed u= 0 km/h

final speed v= 140km/h

time t= 9.8 seconds

Required

The acceleration of the car

Step two:

From a= v-u/t

substitute

a= 140-0/9.8

a=140/9.8

a=14.28 km/h^2

6 0
3 years ago
Simplify<br><br>3+7b+2+2b<br><br>I need to learn how to simplify please<br>​
AVprozaik [17]

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

Answer:

Let's simplify step-by-step.

3 + 7b + 2 + 2b

Combine Like Terms:

= 3 + 7b + 2 + 2b

= ( 7b + 2b ) + ( 3 + 2 )

= 9b + 5

Answer:

= 9b + 5

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

5 0
3 years ago
The motion of a particle is defined by the relation x 5 t 3 2 9t 2 1 24t 2 8, where x and t are expressed in inches and seconds,
shutvik [7]

Answer:

a)  t = 2.0 s,  b)  x_f = - 24.56 m,  Δx = 16.56 m

Explanation:

This is an exercise in kinematics, the relationship of position and time is indicated

          x = 5 t³ - 9t² -24 t - 8

a) ask when the velocity is zero

speed is defined by

         v = \frac{dx}{dt}

let's perform the derivative

        v = 15 t² - 18t - 24

        0 = 15 t² - 18t - 24

let's solve the quadratic equation

      t = \frac{18 \pm \sqrt{18^2 + 4 \ 15 \ 24}  }{2 \ 15}

       t = \frac{18 \pm 42}{30}

       t1 = -0.8 s

      t2 = 2.0 s

the time has to be positive therefore the correct answer is t = 2.0 s

b) the position and distance traveled for a = 0

acceleration is defined by

       a = dv / dt

       a = 30 t - 18

       a = 0

       30 t = 18

       t = 18/30

       t = 0.6 s

we substitute this time in the expression of the position

       

       x = 5 0.6³ - 9 0.6² - 24 0.6 - 8

       x = 1.08 - 3.24 - 14.4 - 8

       x = -24.56 m

we see that all the movement is in one dimension so the distance traveled is the change in position between t = 0 and t = 0.6 s

the position for t = 0

       x₀ = -8 m

the position for t = 0.6 s

      x_f = - 24.56 m

the distance

     ΔX = x_f - x₀

     Δx = | -24.56 -(-8) |

     Δx = 16.56 m

5 0
2 years ago
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