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Elan Coil [88]
4 years ago
5

What happens when you change the frequency of a light wave?

Physics
1 answer:
Nataliya [291]4 years ago
8 0
When you increase the frequency of the waves (assuming amplitude is held constant), the energy of the waves will increase, while wavelength will decrease.. Increase the frequency the light goes toward violet, decrease it and it goes toward red.
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A 5 kilograms bowling ball is dropped out a window. It hits the ground, and bounces upward. The velocity change of the ball is n
ioda

Answer:

13.5

Explanation:

Mass: 5kg

Initial Velocity: -15

Final Velocity: 12

Force: 10

We can use the equation: Vf = Vi + at

We need to find acceleration, and we can use the equation, F=ma,

We have mass and the force so it would look like this, 10=5a, and 5 times 2 would equal 10, so acceleration would be 2.

Now we have all the variables to find time.

Back to Vf = Vi + at, plug the numbers in, 12 = -15 + 2(t)

Plugging them in into desmos gives 13.5 for time.

4 0
2 years ago
When you answer someones question how do you make it so your answer is verified??
malfutka [58]
Well YOU cant make your questions verified. if theres more than one answer to the question the person who asked the question will choose the best answer. usually based upon like how well it explains and if its the right answer
6 0
3 years ago
Read 2 more answers
What are various names of tropical storms<br> based upon the ocean they occur in?
SpyIntel [72]

Answer:

hurricanes,Typhoons and cyclones

4 0
3 years ago
If the rest energies of a positive sigma particle and a lambda particle are 1189.4 and 1115.7 Mev respectively, what is the diff
Lunna [17]

Answer:

1.31022×10⁻³⁴ kg

Explanation:

Difference in energies = 1189.4-1115.7 MeV = 73.7 MeV

Convert this energy to Joules

1 MeV = 1.6×10⁻¹⁹ J

73.7 MeV = 73.7×1.6×10⁻¹⁹ J = 117.92×10⁻¹⁹ J

c = Speed of light = 3×10⁸ m/s

From Einstein's equation

E = mc²

m=\frac{E}{c^2}\\\Rightarrow m=\frac{117.92\times 10^{-19}}{(3\times 10^8)^2}\\\Rightarrow m=1.31022\times 10^{-34}\ kg

∴ Difference in their masses is 1.31022×10⁻³⁴ kg

8 0
3 years ago
A 0.580-kg rock is tied to the end of a string and is swung in a circle with a radius of 0.500 meters. The velocity of the rock
gtnhenbr [62]
F = m  \frac{v^2}{r}

F= 0.58  \frac{4.5^2}{0.5}  = 23.49 N

5 0
3 years ago
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