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3 years ago

Which describes a way to speed up the collisions between hydrogen and oxygen molecules to produce more water?

2 answers:

4 0

<span>Equation:2H2(g) + O2(g) → 2H2O(g)
</span><span>
Smaller container means less volume, and the molecules will hit the walls of the container more frequently because there's less space available and the pressure will go up. I guess this would mean that the side with fewer moles would be favored as a result. We count the number of moles on the reactants and products and find that there are fewer moles on the product side, so I guess this would favor the product formation.

</span>

mariarad [96]3 years ago

4 0

<h2>Equation:2H2(g) + O2(g) → 2H2O(g)</h2>

<h3>Smaller container means less volume, and the molecules will hit the walls of the container more frequently because there's less space available and the pressure will go up. I guess this would mean that the side with fewer moles would be favored as a result. We count the number of moles on the reactants and products and find that there are fewer moles on the product side, so I guess this would favor the product formation.</h3>

You might be interested in

How many atoms of iodine are in 12.75g of CaI2? Hint. How many Iodines are there in one CaI2 particle?

xenn [34]

Answer:

$5.225x10^{22}atoms\ I$

Explanation:

Hello!

In this case, since 12.75 g of calcium iodide has the following number of moles (molar mass = 293.89 g/mol):

$n_{CaI_2}=12.75gCaI_2*\frac{1molCaI_2}{293.89gCaI_2}=0.0434molCaI_2$

In such a way, since 1 mole of calcium iodide contains 2 moles of atoms of iodine, and one mole of atoms of iodine contains 6.022x10²³ atoms (Avogadro's number), we compute the resulting atoms as shown below:

$atoms\ I=0.0434molCaI_2*\frac{2molI}{1molCaI_2} *\frac{6.022x10^{23}atoms\ I}{1molI} \\\\atoms\ I = 5.225x10^{22}atoms\ I$

Best regards!

4 0

3 years ago

What are the benefits and dangers of the Iron element in our daily life?

Digiron [165]

Benefits; helps our red blood cells transport oxygen all around our body

8 0

4 years ago

Which statement concerning the hydrated hydrogen ion is incorrect? (a) Although we often represent hydrogen ions as bare protons

Harrizon [31]

Answer:C. The value of n for H+(H2O)n can be calculated for almost all solutions.

Explanation:

An hydrate can be described as a substance that contains water or with an hydrogen bonded water molecule group.

The hydrate group doesn't necessarily have a fixed formula.

5 0

4 years ago

Please help me out i will give you brainlist. 0.500 is wrong

Alik [6]

<h3>Answer: b) 0.250 mol</h3>

============================================

Work Shown:

Using the periodic table, we see that

1 mole of carbon = 12 grams
1 mole of oxygen = 16 grams

These are approximations and these values are often found underneath the atomic symbol. For example, the atomic weight listed under carbon is roughly 12.011 grams. I'm rounding to 2 sig figs in those numbers listed above.

So 1 mole of CO2 is approximately 12+2*16 = 44 grams. The 2 is there since we have 2 oxygens attached to the carbon atom.

-------------------

Since 1 mole of CO2 is 44 grams, we can use that to convert from grams to moles.

11.0 grams of CO2 = (11.0 grams)*(1 mol/44 g) = (11.0/44) mol = 0.250 mol of CO2

In short,

11.0 grams of CO2 = 0.250 mol of CO2

This is approximate.

We don't need to use any of the information in the table.

3 0

3 years ago

Read 2 more answers

10) an object has mass of 50g 500mg and 0.1g. express the total mass of the object in grams

Pavel [41]

500 mg in g :

1 g ----------- 1000 mg
? -------------- 500 mg

500 x 1 / 1000 => 0.5 g

total mass:

50 g + 0.5 g + 0.1 g => 50.6 g

hope this helps!

8 0

3 years ago