Which describes a way to speed up the collisions between hydrogen and oxygen molecules to produce more water?

2 answers:

4 0

<span>Equation:2H2(g) + O2(g) → 2H2O(g)
</span><span>
Smaller container means less volume, and the molecules will hit the walls of the container more frequently because there's less space available and the pressure will go up. I guess this would mean that the side with fewer moles would be favored as a result. We count the number of moles on the reactants and products and find that there are fewer moles on the product side, so I guess this would favor the product formation.

</span>

mariarad [96]2 years ago

4 0

<h2>Equation:2H2(g) + O2(g) → 2H2O(g)</h2>

<h3>Smaller container means less volume, and the molecules will hit the walls of the container more frequently because there's less space available and the pressure will go up. I guess this would mean that the side with fewer moles would be favored as a result. We count the number of moles on the reactants and products and find that there are fewer moles on the product side, so I guess this would favor the product formation.</h3>

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gayaneshka [121]

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2 years ago

Making methanol the element hydrogen is not abundant in nature, but it is a useful reagent in, for example, the potential synthe

stealth61 [152]

ΔG⁰ = ΔH⁰ - TΔS
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So
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5 0

2 years ago

A 25.0 ml sample of 0.150 m hydrazoic acid is titrated with a 0.150 m naoh solution. what is the ph after 15.0 ml of the sodium

babunello [35]

First, we need to calculate moles of hydrazoic acid NH3:

moles NH3 = molarity * volume

= 0.15 m * 0.025 L

= 0.00375 moles

moles NaOH = molarity * volume

= 0.15 m * 0.015 L

= 0.00225 moles

after that we shoul get the total volume = 0.025L + 0.015L

= 0.04 L

So we can get the concentration of NH3 & NaOH by:

∴[NH3] = moles NH3 / total volume

= 0.00375 moles / 0.04 L

= 0.09375 M

∴[NaOH] = moles NaOH / total volume

= 0.00225 moles / 0.04 L

= 0.05625 M

then, when we have the value of Ka of NH3 so we can get the Pka value from:

Pka = -㏒Ka

= - ㏒ 1.9 x10^-5

= 4.7

finally, by using H-H equation we can get PH:

PH = Pka + ㏒[salt/ basic]

PH = 4.7 +㏒[0.05625/0.09375]

∴ PH = 4.48

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2 years ago

What is the percent composition of hydrogen in vinegar (CH3COOH)?

barxatty [35]

Answer:

%H = 6.72 %

Explanation:

Percent composition of an element is the total mass of that element divided by the molecular mass of compound (or molecular mass) of which it is present in.

So,

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So,

Total Mass of H = 1.01 × 4 = 4.04 g

Molecular Mass of Acetic acid = 60.052 g/mol

Putting values in above formula,

%H = 4.04 g/mol ÷ 60.052 g/mol × 100

%H = 6.72 %

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sdas [7]

All except option two

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3 years ago

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