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-Dominant- [34]
3 years ago
6

What is the word for the definition of an electron in the highest occupied energy level of an atom

Physics
1 answer:
Oliga [24]3 years ago
6 0

<u>Answer:</u> The word for the definition of an electron in the highest occupied energy level of an atom is " valence electron".

<u>Explanation:</u>

A valence electron is an external shell electron associated with an atom in chemistry and physics that can participate in the creation of a chemical bond if the highest occupied energy level of an atom is not closed. All atoms in a single covalent bond add one valence electron to form a mutual pair.

The periodic table showcases the arrangement of valence electrons group and block wise like:

  • Alkali metals have <em>n </em><em>s</em> 1 as external shell configuration like H, Li, Na, K etc.
  • Alkaline metals have <em>n</em> s 2 as external hell configuration like Be, Mg, Ca etc.
  • p-block comprises group 13 to 18 having general electronic configuration <em>n </em><em>s</em> 2, <em>n</em><em> p</em><em> </em>1–6.
  • d-block or transition metals have general electronic configuration (<em>n</em>-1) d 1–10, <em>n </em>s 1–2.
  • f-block or inner transition metals have general electronic configuration (<em>n</em>-2) f^1–14 (<em>n</em>-1) d^0-1 <em>n </em>s^2.
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Find the range of a projectile launched at an angle of 30° with an initial velocity of 20m/s.​
Tems11 [23]

Answer:

<em>The range is 35.35 m</em>

Explanation:

<u>Projectile Motion</u>

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and g=9.8m/s^2 the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:

\displaystyle d={\frac  {v_o^{2}\sin(2\theta )}{g}}

The projectile was launched at an angle of θ=30° with an initial speed vo=20 m/s. Calculating the range:

\displaystyle d={\frac  {20^{2}\sin(2\cdot 30^\circ )}{9.8}}

\displaystyle d={\frac  {400\sin(60^\circ )}{9.8}}

d=35.35\ m

The range is 35.35 m

7 0
3 years ago
You are an engineer in charge of designing a new generation of elevators for a prospective upgrade to the Empire State Building.
katen-ka-za [31]

Answer:

22.505 seconds

Explanation:

V =19.8m/s

V = a*to

t1 = 19.8/3.3

= 6seconds

Distance travelled during acceleration

= 1/2 x 3.3 x 6²

= 59.4m

X_total = x1 + x2

X2 = 373-59.4

X2 = 313.6m

t2 = x2/v

= 313.6/19.8

= 16.505

Total = 16.505 + 6

= 22.505 seconds

the minimum time in which an elevator can travel the 373 m from the ground floor is 22.505 seconds.

7 0
3 years ago
You have two rocks made of the same material that are at the same
mr Goodwill [35]

Answer:

the rocks have the same amount of thermal energy

4 0
3 years ago
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According to the graph of displacement vs. time, what is the object's displacement at time = 60 s?
krek1111 [17]

Answer:

The straight line that is obtained, intercept it on the y-axis and the value of displacement will obtained.

Explanation:

4 0
3 years ago
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Can a body have constant speed and still be acclerating ? Give an Example
Allushta [10]






Hi Pupil Here's Your answer :::





➡➡➡➡➡➡➡➡➡➡➡➡➡





An object moving with constant speed can be accelerated if direction of motion changes. For example, an object moving with a constant speed in a circular path has an acceleration because its direction of motion changes continuously.





⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅






Hope this Helps . . . . . . . . .
3 0
4 years ago
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