The value of x in the given right triangle in a semicircle is determined as 21.
<h3>What is the measure of a triangle in a semicircle?</h3>
The triangle in a semicircle is always a right angle triangle.
From the figure shown, we can say that the triangle G J K is right triangle and m<K = 90degrees.
Given that m<K = 4x + 6, we will can use the following equation to find the value of x as shown:
4x + 6 = 90
4x = 90 - 6
4x = 84
x = 21
Thus, the value of x in the given right triangle in a semicircle is determined as 21.
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Answer:
Option B is the correct answer.
Explanation:
Let us consider 40 meter above ground as origin.
Initial velocity = 17 m/s
Final velocity = 24 m/s
Acceleration = 9.81 m/s
We have equation of motion v² = u² + 2as
Substituting
24² = 17² + 2 x 9.81 x s
s = 14.63 m
Distance traveled by rock = 14.63 m down.
Height of rock from ground = 40 - 14.63 = 25.37 m = 25.4 m
Option B is the correct answer.
If an object's first movement is 3.0m North and another movement is 4.0m west, the magnitude of the overall displacement made would be 5.0 meters in the northwest direction.
<h3>What is displacement?</h3>
Displacement is a vector quantity. This indicates that it has both a direction and a magnitude and that it is visually represented as an arrow that points from the starting position to the ending position.
As given in the problem if an object's first movement is 3.0m North and another movement is 4.0m west
Resultant displacement can be calculated with the help of the triangle law of the vector addition,
Resultant = √( 3² + 4²)
=√25
= 5.0 m
Thus, the magnitude of the overall displacement made would be 5.0 meters in the northwest direction.
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