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3 years ago

Iodine molecules separates into atoms after absorbing light of 450 nm. If one

Physics

1 answer:

OlgaM077 [116]3 years ago

5 0

Answer:E = hc/? = 4.41 x 10-19 J

Energy absorbed by each atom :

E (atom) = 2.205 x 10-19 J

Now Bond Energy of each molecule (B) = 3.98 x J

So, for each atom 1.99 x 10-19 J

So now

KE of each atom = E(atom) - B (atom)

= 2.15 x 10-19 J

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A. How does increasing the voltage of a power supply in an electromagnet affect the strength of the magnetic field?

seropon [69]

PART A)

If we increase the voltage supply in an electromagnet then it will increase the current that is flowing in it

So here due to increase in current there will be increase in the magnetic field due to that electromagnet

PART B)

Here in electric generator the current is produced by rotating a coil between two strong magnets.

So here mechanical energy of rotation of coil is converted into electromagnetic energy.

PART C)

Step up transformer convert the lower voltage input into higher voltage output

here number of turns of coil in output side or secondary number of coils is more than the number of coils in primary side or input side

PART D)

Force on a moving charge is given by

$F = q(\vec v \times \vec B)$

here we know that

q = 0.000600 C

$v = 2.8 \times 10^5 m/s$

B = 4.21 T

now from above equation we have

$F = 0.0006(2.8\times 10^5)(4.21)$

$F = 707.3 N$

direction of force is given by right hand thumb rule

using that rule we got force downwards

7 0

2 years ago

Read 2 more answers

You launch a cannonball at an angle of 35° and an initial velocity of 36 m/s (assume y = y₁=

velikii [3]

Answer:

Approximately $4.2\; {\rm s}$ (assuming that the projectile was launched at angle of $35^{\circ}$ above the horizon.)

Explanation:

Initial vertical component of velocity:

$\begin{aligned}v_{y} &= v\, \sin(35^{\circ}) \\ &= (36\; {\rm m\cdot s^{-1}})\, (\sin(35^{\circ})) \\ &\approx 20.6\; {\rm m\cdot s^{-1}}\end{aligned}$ .

The question assumed that there is no drag on this projectile. Additionally, the altitude of this projectile just before landing $y_{1}$ is the same as the altitude $y_{0}$ at which this projectile was launched: $y_{0} = y_{1}$ .

Hence, the initial vertical velocity of this projectile would be the exact opposite of the vertical velocity of this projectile right before landing. Since the initial vertical velocity is $20.6\; {\rm m\cdot s^{-1}}$ (upwards,) the vertical velocity right before landing would be $(-20.6\; {\rm m\cdot s^{-1}})$ (downwards.) The change in vertical velocity is:

$\begin{aligned}\Delta v_{y} &= (-20.6\; {\rm m\cdot s^{-1}}) - (20.6\; {\rm m\cdot s^{-1}}) \\ &= -41.2\; {\rm m\cdot s^{-1}}\end{aligned}$ .

Since there is no drag on this projectile, the vertical acceleration of this projectile would be $g$ . In other words, $a = g = -9.81\; {\rm m\cdot s^{-2}}$ .

Hence, the time it takes to achieve a (vertical) velocity change of $\Delta v_{y}$ would be:

$\begin{aligned} t &= \frac{\Delta v_{y}}{a_{y}} \\ &= \frac{-41.2\; {\rm m\cdot s^{-1}}}{-9.81\; {\rm m\cdot s^{-2}}} \\ &\approx 4.2\; {\rm s} \end{aligned}$ .

Hence, this projectile would be in the air for approximately $4.2\; {\rm s}$ .

8 0

1 year ago

Read 2 more answers

A student pulls horizontally on a 12 kg box, which then moves horizontally with an acceleration of 0.2 m/s^2. If the student use

polet [3.4K]

The net force of the object is equal to the force applied minus the force of friction.
Fnet = ma = F - Ff
12 kg x 0.2 m/s² = 15 N - Ff
The value of Ff is 12.6 N. This force is equal to the product of the normal force which is equal to the weight in horizontal surface and the coefficient of friction.
Ff = 12.6 N = k(12 kg)(9.81 m/s²)
The value of k is equal to 0.107.

7 0

2 years ago

An object is thrown 16m/s straight up from a 7m tall cliff. How much time does it take to hit the ground below

harkovskaia [24]

Answer:

0,54 sec

Explanation:

t=s/v

t=7/13 s=0,54sec

5 0

3 years ago

Solve the equation x=3logy2 for y.

melisa1 [442]

X = 3 · log(Y²)

X = 3 · 2·log(Y)

X/6 = log(Y)

10^(X/6) = 10^log(Y)

Y = 10^(X/6)

6 0

2 years ago

Read 2 more answers