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Mekhanik [1.2K]
3 years ago
14

Iodine molecules separates into atoms after absorbing light of 450 nm. If one

Physics
1 answer:
OlgaM077 [116]3 years ago
5 0

Answer:E = hc/? = 4.41 x 10-19 J

Energy absorbed by each atom :

E (atom) = 2.205 x 10-19 J

Now Bond Energy of each molecule (B) = 3.98 x J

So, for each atom 1.99 x 10-19 J

So now

KE of each atom = E(atom) - B (atom)

= 2.15 x 10-19 J

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The energy required to ionize magnesium is 738 kj/mol. What minimum frequency of light is required to ionize magnesium
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Answer:

The minimum frequency required to ionize the photon is 111.31 × 10^{37} Hertz

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Energy = 378 \frac{kJ}{mol}

To find:

Minimum frequency of light required to ionize magnesium = ?

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The energy of photon of light is given by,

E = h v

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The energy of photon of light is given by,

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