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vampirchik [111]
3 years ago
15

The intensity of a sound wave increases as the wave spreads out from the source of the sound

Chemistry
1 answer:
Alex3 years ago
5 0

Answer:

The more spread out their energy becomes

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masya89 [10]
Liquid will no pour out. At the bottom the separating funnel consists of a valve it allow the liquid to flow out.The lid is on the top to pour in liquid from the top,it is air tight. Therefore as long as the lid is put, the liquid will not flow out at the bottom. The reason is that ,the incoming air has no way to get into the flask.
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3 years ago
A sample of krypton gas in a container of volume 1.90 L exerts a pressure of 0.553 atm at 21 Celsius. How many moles of gas are
NeTakaya

Explanation:

pv = nRT

n= PV/RT

n =0.553×1.90/0.0821×294

n=1.0507/24.1374

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4 years ago
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3 years ago
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What mass of HgO is required to produce 0.692 mol of O2?<br><br>2HgO(s) -&gt; 2Hg(l) + O2(g)
Vika [28.1K]

The answer for the following problem is mentioned below.

  • <u><em>Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule </em></u>

Explanation:

Given:

no of moles of the oxygen gas = 0.692

Also given:

2 HgO  → 2 Hg + O_{2}

where,

HgO represents mercuric oxide

Hg represents mercury

O_{2} represents oxygen

To calculate:

Molar mass of HgO:

Molar mass of HgO = 216 grams

molar mass of mercury (Hg) = 200 grams

molar mass of oxygen (O) =16 grams

HgO = 200 +16 = 216 grams

We know;

       2×216 grams of HgO   →  1 mole of oxygen molecule

             ?                              →  0.692 moles of oxygen molecule

       

          = \frac{2*216*0.692}{1}

      = 298.944 grams of HgO

<u><em>Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule </em></u>

<u />

7 0
3 years ago
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In which substance does chlorine have an oxidation number of +1?
Anton [14]
The answer is (3) HClO. In the Cl2, chlorine has an oxidation number of zero. In HCl, the oxidation number is -1. In HClO2, the oxidation number is +3. In HClO, it is +1. You can calculate this by using O with oxidation number of -2 and H with +1.
8 0
3 years ago
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