- Let, the maximum height covered by projectile be


- Projectile is thrown with a velocity = v
- Angle of projection = θ
- Velocity of projectile at a height half of the maximum height covered be

______________________________
Then –










- Now, the vertical component of velocity of projectile at the height half of
will be –


Therefore, the vertical component of velocity of projectile at this height will be–
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The unknown liquid has low H+ concentrations and high OH- concentrations.
Answer:
Explanation:
Given
Speed of ball 
Plane is inclined at an angle 
To win the Game we need to hit the target at
away
Launch angle of ball 
Motion of ball can be considered in two planes i.e. Vertical to the plane and horizontal to the plane
So Net acceleration in vertical plane is 
Range of Projectile is given by

for 





so ball must be launched at an angle of 