The mass change, or the mass defect, can be calculated by the formula that is very known to be associated with Albert Einstein. 
E = Δmc²
where
E is the energy gained or released during the reaction
c is the speed of light equal to 3×10⁸ m/s
Δm is the mass change
(1.715×10³ kJ)(1,000 J/1 kJ) = Δm(3×10⁸ m/s)²
Δm = 1.91×10⁻¹¹ kg
        
             
        
        
        
Answer:
carbon, nitrogen,oxygen,flourine
 
        
             
        
        
        
Answer:
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Explanation:
i hope you find this answer
 
        
             
        
        
        
Answer:
Explanation:
Problem 1
<u>1. Data</u>
<u />
a) P₁ = 3.25atm
b) V₁ = 755mL
c) P₂ = ?
d) V₂ = 1325 mL
r) T = 65ºC
<u>2. Formula</u>
Since the temeperature is constant you can use Boyle's law for idial gases:
           
<u>3. Solution</u>
Solve, substitute and compute:
          
         
Problem 2
<u>1. Data</u>
<u />
a) V₁ = 125 mL
b) P₁ = 548mmHg
c) P₁ = 625mmHg
d) V₂ = ?
<u>2. Formula</u>
You assume that the temperature does not change, and then can use Boyl'es law again.
           
<u>3. Solution</u>
This time, solve for V₂:
            
Substitute and compute:
         
You must round to 3 significant figures:
         
Problem 3
<u>1. Data</u>
<u />
a) V₁ = 285mL
b) T₁ = 25ºC
c) V₂ = ?
d) T₂ = 35ºC
<u>2. Formula</u>
At constant pressure, Charle's law states that volume and temperature are inversely related:
          
The temperatures must be in absolute scale.
<u />
<u>3. Solution</u>
a) Convert the temperatures to kelvins:
- T₁ = 25 + 273.15K = 298.15K
 
- T₂ = 35 + 273.15K = 308.15K
 
b) Substitute in the formula, solve for V₂, and compute:
         
You must round to two significant figures: 290 ml
Problem 4
<u>1. Data</u>
<u />
a) P = 865mmHg
b) Convert to atm
<u>2. Formula</u>
You must use a conversion factor.
Divide both sides by 760 mmHg
        
<u />
<u>3. Solution</u>
Multiply 865 mmHg by the conversion factor:
     