Note that we are omitting the water.
So, sodium carbonate will basically dissociate into positive sodium ions and negative carbonate ions based on the following equation:
<span>Na2CO3 → 2 Na(+) + CO3(2-)
</span>
If we took water into consideration:
Sodium carbonate will dissociate in water forming carbonic acid and sodium hydroxide. Since sodium hydroxide is a strong base, therefore, it will then neutralize the gastric acid, thus, acting as an antacid.
The volume of the granite piece in Cm³ is 12.2 cm³
<u><em>calculation</em></u>
volume of granite = (volume of cylinder after placing granite - volume of cylinder before placing granite
= 37.2 ml - 25.0 ml = 12.2 ml
convert ml to Cm³
that is 1 ml = 1 cm³
12.2 ml = ? cm³
<em>by cross multiplication</em>
=(12.2 ml x 1 cm³) / 1 ml = 12.2 cm³
26 elements are man-made ..........
Answer:
41 g
Explanation:
We have a buffer formed by a weak acid (C₆H₅COOH) and its conjugate base (C₆H₅COO⁻ coming from NaC₆H₅COO). We can find the concentration of C₆H₅COO⁻ (and therefore of NaC₆H₅COO) using the Henderson-Hasselbach equation.
pH = pKa + log [C₆H₅COO⁻]/[C₆H₅COOH]
pH - pKa = log [C₆H₅COO⁻] - log [C₆H₅COOH]
log [C₆H₅COO⁻] = pH - pKa + log [C₆H₅COOH]
log [C₆H₅COO⁻] = 3.87 - (-log 6.5 × 10⁻⁵) + log 0.40
[C₆H₅COO⁻] = [NaC₆H₅COO] = 0.19 M
We can find the mass of NaC₆H₅COO using the following expression.
M = mass NaC₆H₅COO / molar mass NaC₆H₅COO × liters of solution
mass NaC₆H₅COO = M × molar mass NaC₆H₅COO × liters of solution
mass NaC₆H₅COO = 0.19 mol/L × 144.1032 g/mol × 1.5 L
mass NaC₆H₅COO = 41 g
Yes, if it’s a parallel circuit the wires are two different wires so it will light because that bulb isn’t connected to the one that went out
