In this item, we are simply to find the ions that may bond and are able to form a formula unit. We are also instructed to give out their name. There are numerous possible combinations of ions to form a compound. Some answers are given in the list below.
1. Na⁺ , Cl⁻ , NaCl ---> sodium chloride (this is most commonly known as table salt)
2. C⁴⁺ , O²⁻ , CO₂ ---> carbon dioxide
3. Al³+ , Cl⁻ , AlCl₃ ----> aluminum chloride
4. Ca²⁺ , Cl⁻ , CaCl₂ ---> calcium chloride
5. Li⁺ , Br⁻ , LiBr ---> lithium bromide
6. Mg³⁺ , O²⁻ , Mg₂O₃ ----> magnesium oxide
7. K⁺ , I⁻ , KI ---> potassium iodide
8. H⁺ , Cl⁻ , HCl --> hydrogen chloride
9. H⁺ , Br⁻ , HBr ----> hydrogen bromide
10. Na⁺ , Br⁻ , NaBr ---> sodium bromide
The flame test is used to visually determine the identity of an unknown metal or metalloid ion based on the characteristic color the salt turns the flame of the bunsen burner
The answer is 0.18
Because the equation for finding the molarity of a solution is:
Moles divided by Liter of solution,
so, you dissolve 0.32 mol of KCL in 1759 ml of Water 1759 ml is 1.759 liters when you plug the numbers in you get 0.18
Hope this helps,
kwrob
Answer:
8.757 x 10^23 molecules
Explanation:
Use Avogadro's number of 6.022
×
10
^23 molecules per mole.
64g CO2/44.01 g/mol = 1.454 moles of CO2
1.454 x 6.022
×
10
^23 =
8.757 x 10^23 molecules
I think it’s C because those elements tend to gain electrons while the deepest shade of green tend to give electrons
