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Andru [333]
3 years ago
8

if a girl is standing in front of a smooth surface from which a sound is reflected, the girl may hear

Physics
1 answer:
Dimas [21]3 years ago
3 0
The girl may hear from the front
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A conducting strip of width 1.5 mm is in a magnetic field. As a result, there is a potential difference of 4.3 mV across the wid
OLga [1]

To solve this problem we will apply the concepts related to the Voltage depending on the Electric field and the distance where it is applied. The relationship of this relationship is given in the following form:

V= Ed \rightarrow E = \frac{V}{d}

Here,

E = Electric Field

V = Voltage

d = Distance

Our values are given as,

d = 1.5mm = 1.5*10^{-3} m

V = 4.3 mV

V = 4.3*10^{-3}V

Replacing at the first equation we have,

E = \frac{4.3*10^{-3}}{1.5*10^{-3}}

E = 2.866V/m

Therefore the electric field in the strip is 2.866V/m

6 0
3 years ago
What is the wavelength of a wave that travels at a speed of 3.0x10^8 m/s and has a frequency of 1.5x10^16 m/s?
Vlad [161]
Speed of wave = wavelength * frequency

Therefore, wavelength is 2.0 x 10^-8
5 0
3 years ago
What has alternating electric and magnetic fields that travel in the form of a wave?
anzhelika [568]

Electromagnetic radiation...

7 0
3 years ago
Removing the radiator cap is advisable as it will help release steam and cool an overheated engine quicker.
stepan [7]

Answer:

False.

Explanation:

Removing the radiator cap will harm you. If the engine is hot and you open the radiator cap then it will cause the liquid boil, pushing the coolant out of the radiator and spraying around the liquid which can harm the person who is opening that cap. So you should aware of the risk and be prepared to avoid danger.

5 0
4 years ago
How many excess electrons must be distributed uniformly within the volume of an isolated plastic sphere 25.0 cm in diameter to p
katrin [286]

Answer:

Required charge q=2.6\times 10^{9}C.

n=1.622\times 10^{10}\ electrons

Explanation:

Given:

Diameter of the isolated plastic sphere = 25.0 cm

Magnitude of the Electric field = 1500 N/C

now

Electric field (E) is given as:

E =\frac{kq}{r^2}

where,

k = coulomb's constant = 9 × 10⁹ N

q = required charge

r = distance of the point from the charge where electric field is being measured

The value of r at the just outside of the sphere = \frac{25.0}{2}=12.5cm=0.125m

thus, according to the given data

1500N/C=\frac{9\times 10^{9}N\times q}{(0.125m)^2}

or

q=\frac{0.125^2\times 1500}{9\times 10^{9}}

or

Required charge q=2.6\times 10^{9}C.

Now,

the number of electrons (n) required will be

n=\frac{required\ charge}{charge\ of\ electron}

or

n=\frac{2.6\times 10^{-9}}{1.602\times 10^{-19}}

or

n=1.622\times 10^{10}\ electrons

6 0
4 years ago
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