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pishuonlain [190]
3 years ago
14

What is the angle θ in the triangle below? (Hint: Use an inverse trigonometric function.)

Physics
1 answer:
Andrej [43]3 years ago
5 0

<u>Answer</u>

The correct answer is B

<u>Explanation</u>

The side length opposite to the angle \theta has length 3 units.

The length of the hypotenuse is 8 units.


We use the trigonometric ratio that involves the length of the opposite side and the hypotenuse, which is

\sin\theta=\frac{Opposite}{Hypotenuse}


\sin\theta=\frac{3}{8}

This is the same as,

\sin\theta=0.375


We take the sine inverse to obtain,

\theta=\sin^{-1}(0.375)

This evaluates to

\theta=22.024


Therefore the value of the angle \theta is 22.0\degree to the nearest tenth





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pishuonlain [190]

Hello!

Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton force is applied to it.

Data:

Hooke represented mathematically his theory with the equation:

F = K * Δx  

On what:

F (elastic force) = 2 N

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Solving:


F = K * \Delta{x}

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\Delta{x} = \dfrac{2\:\diagup\!\!\!\!\!N}{4\:\diagup\!\!\!\!\!N/cm}

simplify by 2

\Delta{x} = \dfrac{2}{4}\frac{\div2}{\div2}

\boxed{\boxed{\Delta{x} = \dfrac{1}{2}\:cm}}\Longleftarrow(distance)\end{array}}\qquad\checkmark

Answer:

B.) 1/2 cm

_______________________

I Hope this helps, greetings ... Dexteright02! =)

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