Not always ammonium salts of weak acids form neutral solutions.
When formic acid reacts with ammonia, ammonium formate is produced:
HCO2H + NH3 ----> NH4HCO2
You already know that the weak conjugate bases of NH3 and HCO2H are NH4+ and HCO2, respectively.
How can the pH of the solution be calculated if the salt's anion causes the pH to rise and the salt's cation causes it to fall? The relative intensities of the basic anion and the acidic cation hold the key to the solution.
As was already established, formate is a weak base and will create hydroxide ions in water, whereas ammonium is a weak acid and will make hydronium ions in water.
NH4⁺ + H2O -----> NH3 + H3O⁺
HCO2⁻ + H2O -----> HCO2H + OH⁻
Since the acid ionization of NH4+ is more favored than the base ionization of HCO2-, the solution will be acidic.
To learn more about ammonium salts:
brainly.com/question/10874844
#SPJ4
CH3COONa+HBr ----> NaBr + CH3COOH
CH3COO⁻ +H⁺ ------> CH3COOH , because CH3COOH is a weak acid
Answer:
Mass = 28.08
Explanation:
Given data:
Mass of Al₂O₃ = 21.8 g
Mass of water = 9.7 g
Mass of Al(OH)₃ = ?
Solution:
Chemical equation:
2Al(OH)₃ → Al₂O₃ + 3H₂O
Number of moles of water:
Number of moles = mass/molar mass
Number of moles = 9.7 g/ 18 g/mol
Number of moles = 0.54 mol
Number of moles of Al₂O₃:
Number of moles = mass/molar mass
Number of moles = 21.8 g/ 101.96 g/mol
Number of moles = 0.21 mol
Now we will compare the moles of Al(OH)₃ with Al₂O₃ and H₂O.
Al₂O₃ : Al(OH)₃
1 : 2
0.21 : 2×0.21 = 0.42 mol
H₂O : Al(OH)₃
3 ; 2
0.54 : 2/3×0.54 = 0.36 mol
Mass of Al(OH)₃:
Mass = number of moles × molar mass
Mass = 0.36 mol × 78 g/mol
Mass = 28.08 g
<h3><u>Ⲁⲛ⳽ⲱⲉⲅ</u><u>:</u></h3>

<h3><u>Ⲋⲟⳑⳙⲧⳕⲟⲛ :</u></h3>
Molarity is used to measure the concentration of a solution , so it is also as molar concentration. It is denoted as M or Mol/L
<u>We </u><u>are </u><u>given </u><u>that </u><u>:</u>
- Weight of
= 5.34g - Volume of solution = 214 ml , or 0.214 L
The molar mass of magnesium chloride (
) is 95.21 g / mol
We can calculate the molarity of the solution by dividing the number of moles of solute by volume of solvent in liter ,i.e:
ㅤㅤㅤ⸻( 1 )
<em>Where,</em><em> </em>
- M = molarity
- n = number of moles
- V = Volume
We can calculate the number of moles by dividing the actual mass by its molar mass ,i.e:
ㅤㅤㅤ⸻ ( 2 )
<em>W</em><em>here,</em>
- n = number of moles
- m = molar mass
- w = actual mass
<u>Therefore</u><u>,</u>



<u>P</u><u>utting </u><u>the </u><u>values </u><u>in </u><u>equation </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u>



The answer is C :
It controls the entry and exit of substances.