Select the correct answer. The gas in a sealed container has an absolute pressure of 9.25 atmospheres. If the air around the con
tainer is at standard pressure, what is the gauge pressure inside the container? A. 0.759 atm B. 8.25 atm C. 10.25 atm D. 113 atm
2 answers:
Answer: B) 8.25 atm.
Explanation: Absolute pressure is the sum of gauge pressure and atmospheric pressure.
Atmosphere pressure is given as 9.25 atm and the atmospheric pressure is 1.00 atm.
Let's plug in the values in the above formula:
9.25 atm = + 1.00 atm
= 9.25 atm - 1.00 atm
= 8.25 atm
So, gauge pressure inside the container is 8,25 atm and hence the right option is B.
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The limiting reactant is iron ore, the theoretical yield of iron metal is 701.344 kg, and the theoretical yield of carbon dioxide is 413.292 kg.
<h3>Stoichiometric problem</h3>From the equation of the reaction:
The mole ratio of iron ore to carbon is 2:3.
Mole of 1000 kg of iron ore = 1000000/159.69
= 6,262 moles
Mole of 120 kg carbon = 120000/12
= 10,000 moles
Thus, it appears that the carbon is in excess while the iron ore is limited in availability.
The mole ratio of the iron ore and the iron produced is 1:2. Thus, the equivalent number of moles of iron produced will be:
6,262 x 2 = 12,524 moles
Mass of 12,524 moles of iron = 12,524 x 56
= 701,344 g or 701.344 kg
Thus, the theoretical yield of iron is 701.344 kg.
The mole ratio of the iron ore and the carbon dioxide produced is 2:3. The equivalent mole of carbon dioxide produced will be:
6,262 x 3/2 = 9,393 moles
Mass of 9,393 moles carbon dioxide = 9,393 x 44
= 413,292 or 413.292 kg
The theoretical yield of carbon dioxide is, therefore, 413.292 kg.
More on stoichiometric problems can be found here: brainly.com/question/14465605
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This is an incomplete question, here is a complete question.
Phosphorus trifluoride is formed from its elements.
How many grams of fluorine are needed to react with 6.20 g of phosphorus?
Answer : The mass of needed are, 11.4 grams.
Explanation : Given,
Mass of = 6.20 g
Molar mass of = 124 g/mol
Molar mass of = 38 g/mol
First we have to calculate the moles of
Now we have to calculate the moles of
The balanced chemical equation is:
From the balanced reaction we conclude that
As, 1 mole of react with 6 moles of
So, 0.05 moles of react with
moles of
Now we have to calculate the mass of
Therefore, the mass of needed are, 11.4 grams.