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Degger [83]
3 years ago
11

Select the correct answer. The gas in a sealed container has an absolute pressure of 9.25 atmospheres. If the air around the con

tainer is at standard pressure, what is the gauge pressure inside the container? A. 0.759 atm B. 8.25 atm C. 10.25 atm D. 113 atm

Chemistry
2 answers:
N76 [4]3 years ago
7 0

Answer:

Explanation:

8.25 atm

yuradex [85]3 years ago
4 0

Answer: B) 8.25 atm.

Explanation: Absolute pressure is the sum of gauge pressure and atmospheric pressure.

P_a_b_s_o_l_u_t_e=P_g_a_u_g_e+P_a_t_m_o_s_p_h_e_r_e

Atmosphere pressure is given as 9.25 atm and the atmospheric pressure is 1.00 atm.

Let's plug in the values in the above formula:

9.25 atm = P_g_a_u_g_e + 1.00 atm

P_g_a_u_g_e = 9.25 atm - 1.00 atm

P_g_a_u_g_e = 8.25 atm

So, gauge pressure inside the container is 8,25 atm and hence the right option is B.

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Calculate the number of grams of sodium chloride in the solution. (Hint: Remember that sodium chloride is a strong electrolyte.)
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The question is incomplete, here is the complete question:

A solution contains 0.115 mol  H_2O and an unknown number of moles of sodium chloride. The vapor pressure of the solution at  30°C  is 25.7 torr. The vapor pressure of pure water at this temperature is 31.8 torr. Calculate the number of grams of sodium chloride in the solution. (Hint: Remember that sodium chloride is a strong electrolyte.)

<u>Answer:</u> The mass of sodium chloride in the solution is 0.714 grams

<u>Explanation:</u>

The formula for relative lowering of vapor pressure will be:

\frac{p^o-p_s}{p^o}=i\times \chi_{\text{solute}}

where,  

p^o = vapor pressure of solvent (water) = 31.8 torr

p^s = vapor pressure of the solution = 25.7 torr

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Putting values in above equation, we get:

\frac{31.8-25.7}{31.8}=2\times \chi_{NaCl}\\\\\chi_{NaCl}=0.0959

Mole fraction of a substance is calculated by using the equation:

\chi_A=\frac{n_A}{n_A+n_B}

\chi_{\text{NaCl}}=\frac{n_{\text{NaCl}}}{n_{\text{NaCl}}+n_{\text{water}}}

We are given:

Moles of water = 0.115 moles

0.0959=\frac{n_{\text{NaCl}}}{n_{\text{NaCl}}+0.115}\\\\n_{\text{NaCl}}=0.0122mol

To calculate the mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of NaCl = 0.0122 moles

Molar mass of NaCl = 58.5 g/mol

Putting values in above equation, we get:

0.0122mol=\frac{\text{Mass of NaCl}}{58.5g/mol}\\\\\text{Mass of NaCl}(0.0122mol\times 58.5g/mol)=0.714g

Hence, the mass of sodium chloride in the solution is 0.714 grams

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