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laiz [17]
3 years ago
8

The first and second coils have the same length, and the third and fourth coils have the same length. They differ only in the cr

oss-sectional area. According to theory, what should be the ratio of the resistance of the second coil to the first coil and the fourth coil to the third
Physics
1 answer:
tatyana61 [14]3 years ago
8 0

Answer:

The ratio of the resistances of second coil to the first coil is the ratio of square of radius of the first coil to the square of radius of  second coil.

And

The ratio of the resistances of fourth coil to the third coil is the ratio of square of radius of the third coil to the square of radius of  fourth coil.

Explanation:

The resistance of the coil is directly proportional to the length of the coil and inversely proportional to the area of coil and hence inversely proportional to the square of radius of the coil.

So, the ratio of the resistances of second coil to the first coil is the ratio of square of radius of the first coil to the square of radius of  second coil.

And

The ratio of the resistances of fourth coil to the third coil is the ratio of square of radius of the third coil to the square of radius of  fourth coil.

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convert 1 milligram to 1 gram:

Explanation:

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A boat is subject to hydrodynamic drag forces of F = 40v 2 [N] where v is the magnitude of velocity in [m/s]. The boat’s mass is
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Answer:

It has moved a distance, S = 25.9 m

Explanation:

F = 40 v²........(1)

F = mv\frac{dv}{dS}.........(2)

Equating (1) and (2)

-mv\frac{dv}{dS} = 40 v^2\\\\v\frac{dv}{dS} = \frac{-40 v^2}{m}  \\\\m = 450 kg\\v\frac{dv}{dS} = \frac{-40 v^2}{450}\\\\ \frac{dv}{v} = \frac{40}{450} dS\\

Integrate both sides:

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\int\limits^{10}_1 {\frac{1}{v} } \, dv = \frac{-40}{450}  \int\limits^S_0  \, dS \\\\ln\frac{1}{10} = \frac{-40}{450} (S-0)\\\\S = \frac{-40}{450} ln(0.1)\\\\S = 25.9 m.

6 0
3 years ago
PREDICT
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Well the block will still have to deal with gravitational force. So here’s my prediction: Although the block is being dropped at different heights it will accelerate at the same speed no matter what and this is due to the earths gravitational energy (9.8m/s^2 or roughly 10m/s^2) so the only thing that will change is the height that the object is dropped.
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3 years ago
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