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3 years ago

Which statement is true?

1 answer:

6 0

A ) Speed is a scalar quantity and velocity is a vector quantity.

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A head-on, elastic collision between two particles with equal initial speed v leaves the more massive particle (mass m1) at rest

ZanzabumX [31]

1/3 The key thing to remember about an elastic collision is that it preserves both momentum and kinetic energy. For this problem I will assume the more massive particle has a mass of 1 and that the initial velocities are 1 and -1. The ratio of the masses will be represented by the less massive particle and will have the value "r" The equation for kinetic energy is E = 1/2MV^2. So the energy for the system prior to collision is 0.5r(-1)^2 + 0.5(1)^2 = 0.5r + 0.5 The energy after the collision is 0.5rv^2 Setting the two equations equal to each other 0.5r + 0.5 = 0.5rv^2 r + 1 = rv^2 (r + 1)/r = v^2 sqrt((r + 1)/r) = v The momentum prior to collision is -1r + 1 Momentum after collision is rv Setting the equations equal to each other rv = -1r + 1 rv +1r = 1 r(v+1) = 1 Now we have 2 equations with 2 unknowns. sqrt((r + 1)/r) = v r(v+1) = 1 Substitute the value v in the 2nd equation with sqrt((r+1)/r) and solve for r. r(sqrt((r + 1)/r)+1) = 1 r*sqrt((r + 1)/r) + r = 1 r*sqrt(1+1/r) + r = 1 r*sqrt(1+1/r) = 1 - r r^2*(1+1/r) = 1 - 2r + r^2 r^2 + r = 1 - 2r + r^2 r = 1 - 2r 3r = 1 r = 1/3 So the less massive particle is 1/3 the mass of the more massive particle.

8 0

3 years ago

Read 2 more answers

Marie Curie and her husband Pierre were Henri Becquerel's graduate students when Becquerel

LenKa [72]

Answer:

It is C on edge.

Explanation:

Because I just figured it out and got it right and because it says so in the link provided from the question.

7 0

3 years ago

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Pls help . Which process produces the energy that is used in photosynthesis?

levacccp [35]

Answer: Nuclear fusion

Explanation:

Have great day!

7 0

3 years ago

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Two satellites are orbiting earth at different altitudes. Which satellite orbits at a higher speed v around earth? Assume that t

alexandr1967 [171]

Answer:

a) the one with a lower orbit b) the one with a higher orbit

Explanation:

Let's consider orbital mechanics. To get an object in orbit, we need it to fall to earth parallel to the earth's surface. To understand it easily imagine a projectile thrown horizontally further and further away, at one point, the projectile hits the cannon from behind. Considering there is no wind resistance, that would be a projecile in orbit.

In other words, the circular orbits of some objects around a massive body are due to the equality between centrifugal acceleration and gravity acceleration.

$\frac{v^2}{r} = \frac{GM}{r^2}$ .

so the velocity is

$v = \sqrt{\frac{GM}{r} }$

where "G" is the gravitational constant, "M" the mass of the massive body and "r" the distance between the object and the center of gravity of mass M. As you can note, if "r" increase, "v" decrease.

The orbital period of any object in orbit is

$T = 2\pi \sqrt{\frac{a^3}{GM} }$

where "a" is length of semi-major axis (a = r in circular orbits). So if "r" increase, "T" increase.

3 0

3 years ago

A spring with k = 53 N/m hangs vertically next to a ruler. The end of the spring is next to the 18 cm mark on the ruler. If a 2.

Anarel [89]

Answer:

1.07 m

Explanation:

x = Compression of the spring

k = Spring constant = 53 N/m

Initial length = 18 cm

P = Kinetic energy

K = Kinetic energy

At the lowest point of the mass the energy conservation is as follows

$P_{ig}+P_{is}+K_i=P_{fg}+P_{fs}+K_f\\\Rightarrow mgx+0+0=mgx+\frac{1}{2}kx^2\\\Rightarrow x=\frac{2mg}{k}\\\Rightarrow x=\frac{2\times 2.4\times 9.81}{53}\\\Rightarrow x=0.89\ m$

At its lowest position the mark on the ruler will be

$x_f=0.18+0.89\\\Rightarrow x_f=1.07\ m$

The spring line will end up at 1.07 m

4 0

3 years ago