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3 years ago

Does a car still have acceleration when it's on cruise control? Explain.

Physics

2 answers:

Vladimir79 [104]3 years ago

4 0

Answer: Yes

because.....

When the cruise control is engaged, the throttle can still be used to accelerate the car. Also,

* Hopefully this helps:) Mark me the brainliest:)!!!

rewona [7]3 years ago

4 0

Yes a car still has acceleration when it’s on cruise control because you can still speed up the car when on cruise but it will just return to its previous speed after

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The mass of an object changes as the distance from the center of gravity changes.

Alchen [17]

Answer:

true

Explanation:

this is the answer to this question

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3 years ago

What do microorganisms get from soil? What do microorganisms give to soil?

nikitadnepr [17]

Answer:

Organic matter decomposition serves two functions for the microorganisms, providing energy for growth and suppling carbon for the formation of new cells. ... Dead plant residues and plant nutrients become food for the microbes in the soil

Explanation:

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3 years ago

1.33 m^3 of fluid flows out of a pipe in 24.5 s. the fluid leaves the pipe at 3.55 m/s. what is the area of the pipe. (unit=m^2)

Margaret [11]

Answer:

0.015 $meter^{2}$

Explanation:

Total volume of water coming out = 1.33 $meter^{3}$

Also volume = Cross sectional area*Length covered

Length covered = Velocity *time

=24.5*3.55

=86.97 meter

Let the cross sectional area be A.

1.33 = 86.97*A

A =0.015 $meter^{2}$

3 0

4 years ago

Read 2 more answers

Electric fields up to 2.00 × 10 5 N/C have been measured inside of clouds during electrical storms. Neglect the drag force due t

katrin2010 [14]

Answer:

$1.9161676647\times 10^{13}\ m/s^2$ or $1.9532799844\times 10^{12}g$

23.4843749996 m

Yes

Explanation:

E = Electric field = $2\times 10^5\ N/C$

c = Speed of light = $3\times 10^8\ m/s$

m = Mass of proton= $1.67\times 10^{-27}\ kg$

q = Charge of electron = $1.6\times 10^{-19}\ C$

Acceleration is given by

$a=\dfrac{Eq}{m}\\\Rightarrow a=\dfrac{2\times 10^5\times 1.6\times 10^{-19}}{1.67\times 10^{-27}}\\\Rightarrow a=1.9161676647\times 10^{13}\ m/s^2$

Dividing by g

$\dfrac{a}{g}=\dfrac{1.9161676647\times 10^{13}}{9.81}\\\Rightarrow a=1.9532799844\times 10^{12}g$

The acceleration is $1.9161676647\times 10^{13}\ m/s^2$ or $1.9532799844\times 10^{12}g$

$v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{(0.1\times 3\times 10^8)^2-0^2}{2\times 1.9161676647\times 10^{13}}\\\Rightarrow s=23.4843749996\ m$

The distance is 23.4843749996 m

The gravitational field is very small compared to the electric field so the effects of gravity can be ignored.

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3 years ago

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Nina [5.8K]

Number 18 is C, i thin

5 0

3 years ago

Read 2 more answers