All categories

3 years ago

What is the first step in problem solving?

Physics

2 answers:

emmasim [6.3K]3 years ago

5 0

Answer:

identify the problem

Explanation:

zmey [24]3 years ago

4 0

The first step in problem solving is of course, identifying the problem. How could you solve the problem if there is no problem in the first place? When one gets to identify the problem, the next step is gathering of information to know more about the problem. One needs to get to know and examine the pros – the benefits – and con – the flaws – of the problem well. After doing all the needed data gathering and possibly, experimentation, when can start looking for the possible solutions of the problem. <span> </span>

You might be interested in

A compact disc (CD) stores music in a coded pattern of tiny pits 10−7m deep. The pits are arranged in a track that spirals outwa

andreev551 [17]

(a) 50 rad/s

The angular speed of the CD is related to the linear speed by:

$\omega=\frac{v}{r}$

where

$\omega$ is the angular speed

v is the linear speed

r is the distance from the centre of the CD

When scanning the innermost part of the track, we have

v = 1.25 m/s

r = 25.0 mm = 0.025 m

Therefore, the angular speed is

$\omega=\frac{1.25 m/s}{0.025 m}=50 rad/s$

(b) 21.6 rad/s

As in part a, the angular speed of the CD is given by

$\omega=\frac{v}{r}$

When scanning the outermost part of the track, we have

v = 1.25 m/s

r = 58.0 mm = 0.058 m

Therefore, the angular speed is

$\omega=\frac{1.25 m/s}{0.058 m}=21.6 rad/s$

(c) 5550 m

The maximum playing time of the CD is

$t =74.0 min \cdot 60 s/min = 4,440 s$

And we know that the linear speed of the track is

v = 1.25 m/s

If the track were stretched out in a straight line, then we would have a uniform motion, therefore the total length of the track would be:

$d=vt=(1.25 m/s)(4,440 s)=5,550 m$

(d) $-6.4\cdot 10^{-3} rad/s^2$

The angular acceleration of the CD is given by

$\alpha = \frac{\omega_f - \omega_i}{t}$

where

$\omega_f = 21.6 rad/s$ is the final angular speed (when the CD is scanned at the outermost part)

$\omega_i = 50.0 rad/s$ is the initial angular speed (when the CD is scanned at the innermost part)

$t=4440 s$ is the time elapsed

Substituting into the equation, we find

$\alpha=\frac{21.6 rad/s-50.0 rad/s}{4440 s}=-6.4\cdot 10^{-3} rad/s^2$

5 0

4 years ago

Read 2 more answers

A machine has a mechanical advantage of 5. What force should be applied to the machine to make it apply 3000 N to an object?

ziro4ka [17]

The answer to this very question is 3000n

6 0

3 years ago

Read 2 more answers

An auto race takes place on a circular track. A car completes one lap in a time of 25.0 s, with an average tangential speed of 5

ludmilkaskok [199]

Answer:

(a) Angular speed will be 0.2512 rad/sec

(b) Radius will be 213.375 m

Explanation:

We have given time to complete 1 lap = 25 sec

We know that 1 lap = $2\pi$ radian

(a) So angular speed $=\frac{2\pi }{25}=\frac{2\times 3.14}{25}=0.2512rad/sec$

(B) Tangential velocity is given as v = 53.6 m/sec

We know that tangential velocity is given by

$v=\omega r$

So radius $r=\frac{v}{\omega }=\frac{53.6}{0.2512}=213.375m$

4 0

3 years ago

Which reaction takes place in a nuclear fission reactor?

anzhelika [568]

Answer:

Last option in the list of possible answers, with U235 and n (neutron) in the left (originators) of the reaction diagram.

Explanation:

Uranium 235 (which is a fissile isotope of uranium) plus slow neutrons is what produce the chain reaction that feeds nuclear reactors.

3 0

3 years ago

What are all the Newton’s laws of motion?

balandron [24]

1st Law Of Motion: An object will often remain at rest or continue moving unless acted upon.
2nd Law Of Motion: Force is equal to mass times acceleration
3rd Law Of Motion: For every action there is an equal or opposite reaction

3 0

3 years ago