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masya89 [10]
3 years ago
13

Ben rushin is waiting at a stoplight. when it finally turns green, ben accelerated from rest at a rate of a 6.00 m/s2 for a time

of 4.10 seconds. determine the displacement of ben's car during this time period
Physics
1 answer:
jasenka [17]3 years ago
4 0

In the 4.10 seconds that elapsed, Ben reaches a velocity of

v_f=v_0+at\implies v_f=0\,\dfrac{\mathrm m}{\mathrm s}+\left(6.00\,\dfrac{\mathrm m}{\mathrm s^2}\right)(4.10\,\mathrm s)

\implies v_f=24.6\,\dfrac{\mathrm m}{\mathrm s}

In this time, his displacement \Delta x satisfies

{v_f}^2-{v_0}^2=2a\Delta x\implies\left(24.6\,\dfrac{\mathrm m}{\mathrm s}\right)^2-\left(0\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(6.00\,\dfrac{\mathrm m}{\mathrm s^2}\right)\Delta x

\implies\Delta x=50.4\,\mathrm m

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Read 2 more answers
A car traveling at 14 m/s accelerates at 3.5 m/s² for 5 seconds. How much distance does it travel during that time?​
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Answer: 113.75

Explanation:

You know

acceleration = a = 3.5 m/s²

time = t = 5 seconds

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Unknown is distance = s = ?

Use equation: s = ut + \frac{1}{2} at²

Substitute all the known values inside the equation:

s = (14*5) + 0.5 * 3.5 * 5²

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3 0
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A sidereal day is the time it takes for
ch4aika [34]

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B. the stars to come back to the same positions in the sky.

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The reason for this is that while performing the rotation, the Earth simultaneously moved following its orbit around the Sun.

When the reference point completed its rotation, the Earth already moved almost 2,500,000 km., So that to see the Sun again it will be necessary to turn a little more.

Solar day is more than a rotation. The sidereal or sidereal day, commonly used by astronomers, is also based on the rotation of the Earth; but in this case a distant star is taken as a reference (sidereal comes from the Latin sidus which means "star").

8 0
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