(a) Determine the circumference of the Earth through the equation,
C = 2πr
Substituting the known values,
C = 2π(1.50 x 10¹¹ m)
C = 9.424 x 10¹¹ m
Then, divide the answer by time which is given to a year which is equal to 31536000 s.
orbital speed = (9.424 x 10¹¹ m)/31536000 s
orbital speed = 29883.307 m/s
Hence, the orbital speed of the Earth is ~29883.307 m/s.
(b) The mass of the sun is ~1.9891 x 10³⁰ kg.
Answer:
Part a)
Part b)
Part c)
Part d)
Net force on a closed loop in uniform magnetic field is always ZERO
Explanation:
As we know that force on a current carrying wire is given as
now we have
Part a)
current in side 166 cm and magnetic field is parallel
so we have
here we know that L and B is parallel to each other so
Part b)
For 68.1 cm length wire we have
here we know that
so we have
Part c)
For 151 cm length wire we have
here we know that
so we have
Part d)
Net force on a closed loop in uniform magnetic field is always ZERO
I believe it is the first one
Answer:
cycles, graphing, precise measurementation
Explanation: