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Veseljchak [2.6K]
3 years ago
8

The enzyme urease catalyzes the breakdown of urea in the body. Urease breaks urea down to 2NH3+CO2. This is an example of a hydr

olysis reaction (urea plus water). For each equivalent of carbon dioxide (CO2), two equivalents of ammonia (NH3) are produced.Label the enzyme, substrate, enzyme

Chemistry
1 answer:
Alika [10]3 years ago
8 0

Answer:

Look at the picture.

Explanation:

On stage one binding of a substrate occurs (and also the geometry of active site may change) and water comes to the site. On stage two the hydrolisis takes place and on stage 3 products deabsorb from the enzyme.

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A container of hydrogen at 172 kPa was decreased to 85.0 kPa producing a new volume of 3L. What was the original volume?
Aneli [31]

Answer:

<h2>The answer is 1.48 L</h2>

Explanation:

In order to find the original volume we use the same for Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the original volume

V_1 =  \frac{P_2V_2}{P_1}  \\

From the question

P1 = 172 kPa = 172000 Pa

P2 = 85 kPa = 85000 Pa

V2 = 3 L

We have

V_1 =  \frac{85000 \times 3}{172000}  =  \frac{255000}{172000}  =  \frac{255}{172}  \\  = 1.482558139...

We have the final answer as

<h3>1.48 L</h3>

Hope this helps you

4 0
3 years ago
What is the [h3o+] for a solution at 25°c that has poh = 5.640?
jonny [76]

Answer:

= 4.37*10^-9 M

Explanation:

We know that;

pH + pOH = 14

Therefore;

pH = 14 - pOH

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But;

pH = -log[H3O+]

Thus;

8.36 = -log[H3O+]

[H3O+] =  10^(-8.36)

        = 4.37*10^-9 M

5 0
3 years ago
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The process by which gasses spontaneously move from an are with higher concentration to one of lower concentration is called diffusion. This process mainly occurs in gases and liquids. The end result of diffusion is called dynamic equilibrium. It is a complete mixing of the molecules  of the gas.
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Answer:

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Explanation:

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Hence options(1)is correct
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