All categories

3 years ago

How does heat differ from temperature?

Chemistry

2 answers:

mote1985 [20]3 years ago

7 0

Answer: Option (c) is the correct answer.

Explanation:

Temperature is used as for measuring the average kinetic energy present in a substance or object.

The internal kinetic energy obtained by the molecules of an object is known as thermal energy.

Hence, temperature measures the thermal energy of an object.

Whereas when this thermal energy flows from a hotter object to a cooler object which are placed adjacent to each other then it is known that heat is flowing.

Thus, we can conclude that heat differ from temperature as temperature measures thermal energy, and heat is the flow of thermal energy.

Lisa [10]3 years ago

4 0

Answer:

C) Temperature measures thermal energy, and heat is the flow of thermal energy.

Explanation:

just took it on edge

You might be interested in

How many atoms of hydrogen combine with one carbon atom to form methane

bonufazy [111]

Answer:four hydrogen atoms

Explanation:

4 0

3 years ago

The radioactivity due to carbon-14 measured in a piece of a wood from an ancient site was found to produce 20 counts per minute

ss7ja [257]

Answer:

The answer is "17200 years".

Explanation:

Given:

$A = 20 \ \frac{counts}{minute}\\\\A_{o} = 160\ \frac{counts}{minute}$

Let the half-life of carbon-14, is beta emitter, is $T = 5730\ years$

Constant decay $\ w = \frac{0.693}{ T}$

$= 1.209 \times 10^{-4} \ \frac{1}{year}\\$

The artifact age $t= ?$

$A = A_{o} e^{-wt} \\\\e^{-wt} = \frac{A}{A_{o}}\\\\-wt = \ln \frac{A}{A_{o}}\\\\= -2.079\\\\t = 1.7199 \times 10^{4} \ years\\\\\sim \ 17200\ years\\$

5 0

3 years ago

The mass of a substance is independent of the amount of the substance, while density depends on the amount of the substance. the

mart [117]

Density is independent of amount while mass is dependent

6 0

4 years ago

Nitrogen (N2) enters a well-insulated diffuser operating at steady state at 0.656 bar, 300 K with a velocity of 282 m/s. The inl

Tasya [4]

Answer:

The exit temperature of the Nitrogen would be 331.4 K.
The area at the exit of the diffuser would be $7*10^{-3} m^2$ .
The rate of entropy production would be 0.

Explanation:

First it is assumed that the diffuser works as a isentropic device. A isentropic device is such that the entropy at the inlet is equal that the entropy T the exit.
It will be used the subscript 1 for the inlet conditions of the nitrogen, and the subscript 2 for the exit conditions of the nitrogen.
It will be called: v the velocity of the nitrogen stream, T the nitrogen temperature, V the volumetric flow of the specific stream, A the area at the inlet or exit of the diffuser and, P the pressure of the nitrogen flow.
It is known that for a fluid flowing, its volumetric flow is obtain as: $V=v*A$ ,
Then for the inlet of the diffuser: $V_1=v_1*A_1=282\frac{m}{s}*4.8*10^{-3}m^2=1.35\frac{m^3}{s}$
For an ideal gas working in an isentropic process, it follows that: $\frac{T_{2} }{T_1}=(\frac{P_2}{P_1})^k$ where each variable is defined according with what was presented in step 2 and 3, and k is the heat values relationship, 1.4 for nitrogen.
Then solving for $T_2$ , the temperature of the nitrogen at the exit conditions: $T_2=T_1(\frac{P_2}{P_1})^k$ then, $T_2=300 K (\frac{0.9 bar}{0.656 bar})^{(\frac{1.4-1}{1.4})}=331.4 K$
Also, for an ideal gas working in an isentropic process, it follows that: $\frac{P_2}{P_1}= (\frac{V_1}{V_2})^k$ , where each variable is defined according with what was presented in step 2 and 3, and k is the heat values relationship, 1.4 for nitrogen.
Then solving for $V_2$ the volumetric flow at the exit of the diffuser: $V_2=V_1*\frac{1}{\sqrt[k]{\frac{P_2}{P_1}}}=\frac{1.35\frac{m^3}{s}}{\sqrt[1.4]{\frac{0.9bar}{0.656bar} }}=1.080\frac{m^3}{s}$ .
Knowing that $V_2=1.080\frac{m^3}{s}$ , it is possible to calculate the area at the exit of the diffuser, using the relationship presented in step 4, and solving for the required parameter: $A_2=\frac{V_2}{v_2}=\frac{1.08\frac{m^3}{s} }{140\frac{m}{s}}=7.71*10^{-3}m^2$ .
To determine the rate of entropy production in the diffuser, it is required to do a second law balance (entropy balance) in the control volume of the device. This balance is: $S_1+S_{gen}-S_2=\Delta S_{system}$ , where: $S_1$ and $S_2$ are the entropy of the stream entering and leaving the control volume respectively, $S_{gen}$ is the rate of entropy production and, $\Delta S_{system}$ is the change of entropy of the system.
If the diffuser is operating at stable state is assumed then $\Delta S_{system}=0$ . Applying the entropy balance and solving the rate of entropy generation: $S_{gen}=S_2-S_1$ .
Finally, it was assume that the process is isentropic, it is: $S_1=S_2$ , then $S_{gen}=0$ .

6 0

3 years ago

Which of the following changes will decrease the total amount of gaseous solute able to be dissolved in a liter of liquid water?

Scrat [10]

A gaseous solute will be able to be dissolve in a liter of liquid water by increasing the pressure of the gas. an example of this situation is the increase in solubility of carbon dioxide in sea water which turns it into an acidic environment for marines as pressure increases.

3 0

3 years ago

Read 2 more answers