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Jet001 [13]
3 years ago
7

Keiko needs 100mL of a 5% acid solution for a science experiment. She has available a 1% solution and a 6% solution. How many mi

lliliters of the 1% solution and how many milliliters of the 6% solution should she mix to make the 5% solution?

Chemistry
2 answers:
4vir4ik [10]3 years ago
7 0

Answer:

Keiko should mix 20 mL 1% solution and 80 mL 6% solution for to make 100 mL 5% solution

Explanation:

There are 2 unknown values X= mL 6% solution and Y=1% solution. So, we need 2 equations:

1. Equation acid concentration. X mL 6% + Y mL 1% = 100 mL 5%

2. Equation solvent concentration X mL 94% + Y mL 99% = 100 mL 95%

When clearing X and Y :

(X mL 6%    +   Y mL 1%      =    100 mL 5%) (-15,7)

X mL 94%  +   Y mL 99%   =   100 mL 95%

_______________________________

 -                      Y  0.83       =   16.5

                        Y                =   19.9 mL 1% solution

Replace Y in anyone equation and X = 80 mL 6% solution

I hope to see been helpful

umka2103 [35]3 years ago
4 0

20 ml of the 1% solution and 80 ml of the 6% solution should she mix to make the 100 ml of 5% solution

<h3>Further explanation </h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. Concentration shows the amount of solute in a unit of the amount of solvent.

Molarity (M)

Molarity shows the number of moles of solute in every 1 liter of solution.

\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = volume of the solution

For molarity a mixture can be formulated  :

M_{mix}=\frac{total\:mole}{total\:volume}

M_{mix}=\frac{M1.V1+M2.V2}{V1+V2}

Keiko needs 100 mL of a 5% acid solution

The available solutions are 1% and 6%

We can make a mathematical equation from the two statements above

  • 1. V1 + V2 = 100

The total volume of the 1% and 6% solutions is 100 ml

  • 2. The mixture concentration is 5%

5% = 1% .V1 + 6% .V2 /( V1 + V2 )

5% = 1% .V1 + 6% .V2 / 100

5 = 1% .V1 + 6% .V2 or

500 = V1 + 6V2

Equations 1 and 2 we do elimination and substitution

500 = V1 + 6V2

100  = V1 + V2

----------------------- -

400 =  5V2

V2 = 80 ml

V1 = 20 ml

<h3>Learn more </h3>

the concentrations for the two ions

brainly.com/question/8574523

The molarity of the stock solution of luminol

brainly.com/question/2814870

volume of 0.100 M Na₃PO₄

brainly.com/question/2284993

Keywords: reaction coefficients, potassium carbonate, electrolytes

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