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3 years ago

What is the difrence beetween thermal energy and temperature

2 answers:

8 0

Answer: The difference between temperature and thermal energy is that temperature measures the average kinetic speed of molecules and thermal energy is the total kinetic energy of all particles in a given substance

Explanation:

bagirrra123 [75]3 years ago

6 0

Answer:

Hope this helps

Explanation:

Thermal energy, which is more commonly known as heat, is a form of energy. It is measured in joules. Thermal energy is an internal energy for a given system. Thermal energy is the cause for the temperature of a system.

Temperature is the measureable thermal property of a system. It is measured in Kelvin, Celsius, or Fahrenheit. The SI unit for temperature measurement is Kelvin.

Differences:

Thermal energy is not a directly measurable quantity whereas temperature is a measurable quantity.

• The temperature of an object can take negative values depending on the unit system used to measure the temperature, but the thermal energy of a system cannot be negative.

• Temperature is measured in Kelvin whereas thermal energy is measured in Joule.

• An object can lose or gain thermal energy in a state transition without changing the temperature of the system.

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Which 2 elements when combined NOT alloys?

Volgvan

Answer:

Oxygen and sulfur

Explanation:

Alloys consist of metals fused together sometimes with additional components, such as carbon, to prevent metals from corrosion.

Oxygen and sulfur are two compounds consisting of non-metal atoms, O and S. Combining oxygen with sulfur would actually produce sulfur dioxide, a gas, in contrast to a metallic substance that is fused with some other metal or carbon.

That's the reason why combination of sulfur and oxygen wouldn't produce an alloy: it would produce a gas.

6 0

2 years ago

Saturated hydrocarbons are major components of

cupoosta [38]

Answer:

gasoline

Explanation:

....................

4 0

2 years ago

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Which salt contains an ion that forms a colored solution?

Orlov [11]

<span>Ni(NO₃)₂ - salt that forms a colored solution</span>

8 0

2 years ago

3.15.8 cm3 of H2SO4 completely neutralised 20 cm3 of NaOH. The NaOH was 1.5 mol/dm3.

Furkat [3]

Answer:

Molarity = 0.95 mol/dm³

Explanation:

Given data:

Volume of H₂SO₄ = 15.8 cm³

Volume of NaOH = 20 cm³

Concentration of NaOH = 1.5 mol/dm³

Concentration of H₂SO₄ = ?

Solution:

Chemical equation:

NaOH + H₂SO₄ → Na₂SO₄ + H₂O

First of all we will calculate the number of moles of NaOH and for that we will convert the units first,

Volume = 20 cm³/1000 = 0.02 L

Concentration of NaOH = 1.5 mol/dm³

1 mol/dm³ = 1 mol/L

Concentration of NaOH = 1.5 mol/L

Number of moles of NaOH:

Molarity = number of moles / volume in L

1.5 M = number of moles / 0.02 L

Number of moles = 1.5 M ×0.02 L

Number of moles = 0.03 mol

Now we will compare the moles of NaOH and H₂SO₄

NaOH : H₂SO₄

2 : 1

0.03 : 1/2×0.03 = 0.015 mol

Concentration of H₂SO₄:

Volume of H₂SO₄:

15.8 cm³/1000 = 0.0158 L

Molarity = number of moles / volume in L

Molarity = 0.015 mol / 0.0158 L

Molarity = 0.95 mol/L

1 mol/L = 1 mol/dm³

Molarity = 0.95 mol/dm³

6 0

2 years ago

The volumetric analysis of mixture of gases is 30 percent oxygen, 40 percent nitrogen, 10 percent carbon dioxide, and 20 percent

SOVA2 [1]

Answer: $Q=234kJ/kg$

Explanation:

Hello,

In this case, the transferred heat to the mixture is given by the addition among each compound's specific enthalpies:

$Q=h_{O_2}+h_{N_2}+h_{CO_2}+h_{CH_4}$

Now, each specific enthalpy is given by the following equation:

$h_i=\int\limits^{T_2}_{T_1} {Cp_i(T)} \, dT$

As long as there is a large difference between the initial and the final temperature. In such a way, the shown below polynomial for the Cp which is given kJ/kmol*K is considered and subsequently integrated:

$Cp(T)=a+bT+cT^2+dT^3\\\int\limits^{T_2}_{T_1} {Cp(T)} \, dT =a(T_2-T_1)+\frac{b}{2}(T_2^2-T_1^2)+\frac{c}{3}(T_2^3-T_1^3)+\frac{d}{4}(T_2^4-T_1^4)$

Now, the specific enthalpy is computed for each component considering the temperatures in Kelvin:

$h_{O_2}=25.48(473.15K-293.15K)+\frac{1.520x10^{-2}}{2}(473.15K^2-293.15K^2)+\frac{-0.7155x10^{-5}}{3}(473.15K^3-293.15K^3)+\frac{1.312x10^{-9}}{4}(473.15K^4-293.15K^4)=5456.2kJ/kmol$

$h_{N_2}=28.9(473.15K-293.15K)+\frac{-0.1571x10^{-2}}{2}(473.15K^2-293.15K^2)+\frac{0.8081x10^{-5}}{3}(473.15K^3-293.15K^3)+\frac{-2.873x10^{-9}}{4}(473.15K^4-293.15K^4)=5280.4kJ/kmol\\$

$h_{CO_2}=22.26(473.15K-293.15K)+\frac{5.981x10^{-2}}{2}(473.15K^2-293.15K^2)+\frac{-3.501x10^{-5}}{3}(473.15K^3-293.15K^3)+\frac{7.469x10^{-9}}{4}(473.15K^4-293.15K^4)=7269.4kJ/kmol\\$

$h_{CH_4}=19.89(473.15K-293.15K)+\frac{5.024x10^{-2}}{2}(473.15K^2-293.15K^2)+\frac{1.269x10^{-5}}{3}(473.15K^3-293.15K^3)+\frac{-11.01x10^{-9}}{4}(473.15K^4-293.15K^4)=7269kJ/kmol\\$

Now, we convert them per unit of mass as:

$h_{O_2}=5456.2kJ/kmol*\frac{1kmol}{32kg}=170.5kJ/kg\\h_{N_2}=5280.4kJ/kmol*\frac{1kmol}{28kg}=188.6kJ/kg\\h_{CO_2}=7269.4kJ/kmol*\frac{1kmol}{44kg}=165.2kJ/kg\\h_{CH_4}=7269kJ/kmol*\frac{1kmol}{16kg}=454.3kJ/kg$

Finally, by considering the volumetric percentages, we compute the heat transferred to mixture:

$Q=0.3*170.5kJ/kg+0.4*188.6kJ/kg+0.1*165.2kJ/kg+0.2*454.3kJ/kg\\Q=234kJ/kg$

Best regards.

6 0

2 years ago