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3 years ago

What is the difrence beetween thermal energy and temperature

2 answers:

8 0

Answer: The difference between temperature and thermal energy is that temperature measures the average kinetic speed of molecules and thermal energy is the total kinetic energy of all particles in a given substance

Explanation:

bagirrra123 [75]3 years ago

6 0

Answer:

Hope this helps

Explanation:

Thermal energy, which is more commonly known as heat, is a form of energy. It is measured in joules. Thermal energy is an internal energy for a given system. Thermal energy is the cause for the temperature of a system.

Temperature is the measureable thermal property of a system. It is measured in Kelvin, Celsius, or Fahrenheit. The SI unit for temperature measurement is Kelvin.

Differences:

Thermal energy is not a directly measurable quantity whereas temperature is a measurable quantity.

• The temperature of an object can take negative values depending on the unit system used to measure the temperature, but the thermal energy of a system cannot be negative.

• Temperature is measured in Kelvin whereas thermal energy is measured in Joule.

• An object can lose or gain thermal energy in a state transition without changing the temperature of the system.

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How many moles of oxygen are contained in. 752 moles of calcium carbonate?

Nitella [24]

Answer:

2.256 moles of oxygen atoms

Explanation:

CaCo3 is calcium carbonate

every mole of calc carb has 3 moles of O atoms

.752 moles of this has 3 times as many moles of Oxygen atoms

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2 years ago

Which product of petroleum is normally used as fuel in cars and light vehicles

Elena L [17]

Answer:

mostly gasoline in cars nowadays

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3 years ago

Read 2 more answers

Sodium tert-butoxide (NaOC(CH3)3) is classified as bulky and acts as Bronsted Lowry base in the reaction. It is reacted with 2-c

IceJOKER [234]

Answer:but-1-ene

Explanation:This is an E2 elimination reaction .

Kindly refer the attachment for complete reaction and products.

Sodium tert-butoxide is a bulky base and hence cannot approach the substrate 2-chlorobutane from the more substituted end and hence major product formed here would not be following zaitsev rule of elimination reaction.

Sodium tert-butoxide would approach from the less hindered side that is through the primary centre and hence would lead to the formation of 1-butene .The major product formed in this reaction would be 1-butene .

As the mechanism of the reaction is E-2 so it will be a concerted mechanism and as sodium tert-butoxide will start abstracting the primary hydrogen through the less hindered side simultaneously chlorine will start leaving. As the steric repulsion in this case is less hence the transition state is relatively stabilised and leads to the formation of a kinetic product 1-butene.

Kinetic product are formed when reactions are dependent upon rate and not on thermodynamical stability.

2-butene is more thermodynamically6 stable as compared to 1-butene

The major product formed does not follow the zaitsev rule of forming a more substituted alkene as sodium tert-butoxide cannot approach to abstract the secondary proton due to steric hindrance.

5 0

3 years ago

When a student chemist transferred the metal to the calorimeter, some water splashed out of the calorimeter. will this technique

Natalka [10]

Answer:

It will be reported too low.

Explanation:

To measure the specific heat of the metal (s), the calorimeter may be used. In it, the metal will exchange heat with the water, and they will reach thermal equilibrium. Because it can be considered an isolated system (there're aren't dissipations) the total amount of heat (lost by metal + gained by water) must be 0.

Qmetal + Qwater = 0

Qmetal = -Qwater

The heat is the mass multiplied by the specific heat multiplied by the temperature change. If c is the specific heat of the water:

m_metal*s*ΔT_metal = - m_water *c*ΔT_water

s = -m_water *c*ΔT_water / m_metal*ΔT_metal

So, if m_water is now less than it was supposed to be, s will be reported too low, because they are directly proportional.

5 0

3 years ago

Answer the following questions based on the reaction below: NaOH(aq) + KHP(s) --> NaKP(aq)+H2O(I)

Natali [406]

Answer:

a) 1.44g

b) 77.3%

Explanation:

1. Chemical balanced equation (given)

$NaOH(aq)+ KHP(s)\rightarrow NaKP(aq)+H_2O(l)$

2. Mole ratio

$1molNaOH(aq):1molKHP(s)$

This is, 1 mol of NaOH will reacts with 1 mol of KHP.

3. Find the number of moles in 72.14 mL of the base

$Molarity=\text{number of moles of solute}/\text{volume of solution in liters}$

$\text{Volume of solution}=72.14mL=0.07214liters$

$\text{Number of moles of NaOH}=0.0978M\times 0.07214liter=0.007055mol$

4. Find the number of grams of KHP that reacted

The number of moles of KHP that reacted is equal to the number of moles of NaOH, 0.007055 mol

Convert moles to grams:

mass = number moles × molar mass = 0.007055mol × 204.23g/mol

mass = 1.4408 g.

You have to round to 3 significant figures: 1.44 g (because the molarity is given with 3 significant figures).

5. Find the percentage of KHP in the sample

The percentage is how much of the substance is in 100 parts of the sample.

The formula is:

% = (mass of substance / mass of sample) × 100

% = (1.4408g/ 1.864g) × 100 = 77.3%

7 0

3 years ago