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The orbital period of the satellite[T] is given as .
The radius of the satellite is given [R] .
we are asked here to calculate the tangential speed of the satellite.
Before going to get the solution first we have understand the tangential speed.
The tangential speed of a satellite is given as the speed required to keep the satellite along the orbit. If satellite speed is less than tangential speed,there is the chance of it falling down towards earth. If it is more,then it will deviate from it orbit and can't stick to the orbit further.In a simple way the tangential speed is the linear speed of an object in a circular path.
Now we have to calculate the tangential speed [V].
Mathematically the tangential speed [V] written as -
V
where T is the time period of the satellite and R is the radius of the satellite.
There is also another way through which we can get the solution as explained below-
We know that the tangential speed of a satellite V
where G is the gravitational constant and M is the mas of central object.
But we know that
⇒ where g is the acceleration due to gravity of that central object.
Hence
⇒
By knowing the value of g due to that central object we can also calculate its tangential speed.
The kinematics and conservation of momentum relationships allow to find the results for the questions about the measurements and conditions to know the accident conditions are:
1) The principles of conservation of momentum and kinematics.
2)
3) The factors that influence the direction and distance traveled are:
The initial speed of the vehicles
The mass of the vehicles
Pavement conditions: dry, wet, humid, with dirt or loose sand.
1) Kinematics studies the movement of bodies, they look for relationships between position, speed and acceleration.
To analyze the accident, you must answer a question such as what speed the vehicles had before the accident, this is the initial speed of each one and their directions.
When reviewing the kinematics relationships we have.
Where the acceleration is given by Newton's second law.
fr = m a
The friction force is given by the expression.
fr = μ N
fr = μ mg
Let's Substitute.
μ m g = m a
a = μ g
The friction coefficient is tabulated, for different types of rubber, pavement and wet, dry conditions, etc.
Therefore, the researcher must measure the braking distance of the vehicles, which can be taken from the mark of the tires on the road and note the condition of the pavement if it is dry or wet and the visibility of the day.
This is the speed of the vehicles just after the impact, using the law of conservation of momentum you can find the speed of the vehicles before the impact
\f
Where this is a vector expression, which in general is solved with the components of each directional.
Consequently to answer the questions you must use the principles of conservation of momentum and kinematics.
2) If the vehicles travel at right angles and their masses are similar, the direction after the collision in each direction.
3) The factors that influence the direction and distance traveled are:
The initial speed of the vehicles
The mass of the vehicles
Pavement conditions: dry, wet, humid, with dirt or loose sand.
In conclusion, using the kinematics and conservation of momentum relationships, we can find the answers to the question about measurements and conditions to know the accident conditions are:
1) The principles of conservation of momentum and kinematics.
2)
3) The factors that influence the direction and distance traveled are:
The initial speed of the vehicles
The mass of the vehicles
Pavement conditions: dry, wet, humid, with dirt or loose sand.
Learn more about kinematics and momentum here: brainly.com/question/17304001