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Alchen [17]
3 years ago
14

Technician A says that a common cause of parking brakes that will not hold, is out of adjustment slack adjusters. Technician B s

ays that loss of pressure in the secondary circuit can cause poor trailer parking brake performance. Who is correct?a) technician Ab) technician Bc) both technicians A and Bd) neither technician A nor B
Physics
1 answer:
Flauer [41]3 years ago
6 0

Answer:

a) technician A

Explanation: A parking brake is a secondary and support brake system which is usually applied when the vehicle is not in motion,this is done to prevent any form of motion and the possibility of any form of accident.

A secondary circuit is a circuit or coil in which current is generated through induction from another circuit or coil called the primary circuit,it has not been discovered that a low pressure from that circuit has led to poor trailer parking brake performance.

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3 years ago
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A golf club hits a 0.04551 kg golf ball off a golf tee. The club is in contact with the ball for 0.020 s, and the force applied
Juliette [100K]

Answer:

v = 50.5 m/s

Explanation:

F = (m)(^v/^t)

115N = (0.04551kg)(v/(0.020s))

2,526.917161 m/s² = v/(0.020s)

v = 50.53834322 m/s

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8 0
3 years ago
After being struck by a bowling ball, a 1.8 kg bowling pin sliding to the right at 5.0 m/s collides head-on with another 1.8 kg
kaheart [24]

Answer:

a) v₂ = 4.2 m/s

b) v₂ = 5 m/s

Explanation:

a)

We will use the law of conservation of momentum here:

m_1u_1+m_2u_2=m_1v_1+m_2v_2

where,

m₁ = m₂ = mass of bowling pin = 1.8 kg

u₁ = speed of first pin before collsion = 5 m/s

u₂ = speed of second pin before collsion = 0 m/s

v₁ = speed of first pin after collsion = 0.8 m/s

v₂ = speed of second after before collsion = ?

Therefore,

(1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0.8\ m/s)+(1.8\ kg)(v_2)\\v_2 = 5\ m/s - 0.8\ m/s

<u>v₂ = 4.2 m/s</u>

<u></u>

b)

We will use the law of conservation of momentum here:

m_1u_1+m_2u_2=m_1v_1+m_2v_2

where,

m₁ = m₂ = mass of bowling pin = 1.8 kg

u₁ = speed of first pin before collsion = 5 m/s

u₂ = speed of second pin before collsion = 0 m/s

v₁ = speed of first pin after collsion = 0 m/s

v₂ = speed of second after before collsion = ?

Therefore,

(1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0\ m/s)+(1.8\ kg)(v_2)

<u>v₂ = 5 m/s</u>

5 0
3 years ago
5. The condition of the road surface affects total stopping distance.<br>A. true<br>B. false​
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Answer:

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4 years ago
A wave has a wavelength of 8 mm and a frequency of 11 hertz. What is its speed? Your Answer:?
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To find wave speed, you multiply the wavelength by the frequency. This means it is 8 times 11. This gives you 88. That means the answer is 88mm/s

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4 years ago
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