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3 years ago

The water table is the...

Chemistry

1 answer:

vovangra [49]3 years ago

3 0

B upper boundary of the zone of saturation, land beneath this line is saturated with water.

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How many moles of ammonium sulfate can be from the reaction of 30.0 mol of NH3 with H2SO4 according to the following equation: 2

marysya [2.9K]

Answer:

15 moles of ammonium sulfate would be formed from 30 moles of ammonia.

Explanation:

Given data:

Number of moles of ammonium sulfate formed = ?

Number of moles of ammonia = 30.0 mol

Solution:

Chemical equation:

2NH₃ + H₂SO₄ → (NH₄)₂SO₄

Now we will compare the moles of ammonium sulfate with ammonia.

NH₃ : (NH₄)₂SO₄

2 : 1

30.0 : 1/2×30.0 = 15.0 mol

So 15 moles of ammonium sulfate would be formed from 30 moles of ammonia.

7 0

3 years ago

"Calculate the number of millimoles in 500 mg of each of the following amino acids: alanine (MW = 89), leucine (131), tryptophan

Cloud [144]

Answer:

- Alanine = 5.61 mmoles

- Leucine = 3.81 mmoles

- Tryptophan = 2.45 mmoles

- Cysteine = 4.13 mmoles

- Glutamic acid = 3.40 mmoles

Explanation:

Mass / Molar mass = Moles

Milimoles = Mol . 1000

500 mg / 1000 = 0.5 g

- Alanine = 0.5 g / 89 g/m → 5.61x10⁻³ moles . 1000 = 5.61mmoles

- Leucine = 0.5 g / 131 g/m → 3.81 x10⁻³ moles . 1000 = 3.81 mmoles

- Tryptophan = 0.5 g / 204 g/m → 2.45x10⁻³ moles . 1000 = 2.45 mmoles

- Cysteine = 0.5 g / 121 g/m → 4.13x10⁻³ moles . 1000 = 4.13 mmoles

- Glutamic acid = 0.5 g 147 g/m → 3.40x10⁻³ moles . 1000 = 3.4 mmoles

5 0

3 years ago

A mileage test is conducted for a new car model. Thirty randomly selected cars are driven for a month and the mileage is measure

Leni [432]

Answer: $(27.81,\ 29.39)$

Explanation:

Given : Sample size : n= 30 , it means it is a large sample (n≥ 30), so we use z-test .

Significance level : $\alpha: 1-0.95=0.05$

Critical value: $z_{\alpha/2}=1.96$

Sample mean : $\overline{x}=28.6$

Standard deviation : $\sigma=2.2$

The formula to find the confidence interval is given by :-

$\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

i.e. $28.6\pm (1.96)\dfrac{2.2}{\sqrt{30}}$

i.e. $28.6\pm 0.787259889321$

$\approx28.6\pm 0.79=(28.6-0.79,28.6+0.79)=(27.81,\ 29.39)$

Hence, the 95% confidence interval for the mean mpg in the entire population of that car model = $(27.81,\ 29.39)$

4 0

3 years ago

The law of conservation of mass states that mass is neither created nor destroyed during a chemical reaction. This can be gleane

GenaCL600 [577]

Answer : The total mass of oxygen gas released in the reaction will be, 12.8 grams

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

$2MgO\rightarrow 2Mg+O_2$

According to the law of conservation of mass,

Total mass of reactant side = Total mass of product side

Total mass of $2MgO$ = Total mass of $2Mg+O_2$

or,

Total mass of $2MgO$ = Mass of $2Mg$ + Mass of $O_2$

As we are given :

Total mass of $MgO$ = 16.12 grams

The mass of $Mg$ = 9.72 grams

So,

Total mass of $2MgO$ = Mass of $2Mg$ + Mass of $O_2$

$2\times 16.12g=2\times 9.72g+\text{Mass of }O_2$

$\text{Mass of }O_2=32.24g-19.44g=12.8g$

Therefore, the total mass of oxygen gas released in the reaction will be, 12.8 grams

8 0

3 years ago

You are working in a lab when radiation alarms go off. You are able to hide inside a steel cabinet, whose sides are about 1.5 in

dusya [7]

Answer:

Its either B or C (in my opinion)

6 0

3 years ago