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Andre45 [30]
3 years ago
14

About how far did the animal travel in 1 second

Physics
1 answer:
Stella [2.4K]3 years ago
7 0

Answer:

one step UVU i dont even know XD there is no picture or graph?

Explanation:

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An object that is speeding up is accelerating.<br> True<br> False
Stels [109]
True. The speed of any object will have faster acceleration, and eventually slow down due to gravity.
3 0
2 years ago
a student is pushing a 50 kilogram cart with a force of 500 newtons another students measures the speed of the cart and finds th
Irina-Kira [14]

The force of friction is 300 N

Explanation:

We can solve the problem by applying Newton's second law of motion: in fact, the net force acting on an object is equal to the product between the mass of the object and its acceleration. So we can write

\sum F = ma

where

\sum F is the net force acting on the object

m is its mass

a is its acceleration

For the cart in this problem, we have two forces acting on it:

- The force of push, F = 500 N, forward

- The force of friction, F_f, backward

So Newton's second law can be rewritten as

F-F_f = ma

where

m = 50 kg

a=4 m/s^2 is the acceleration of the cart

And solving for F_f, we find the force of friction:

F_f = F-ma=500-(50)(4)=300 N

Learn more about force of friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

#LearnwithBrainly

4 0
2 years ago
A resistor with an unknown resistance is connected in parallel to a 13 ? resistor. when both resistors are connected in parallel
DENIUS [597]
Hope this helps you.

4 0
3 years ago
Location C is 0.02 m from a small sphere which has a charge of 3 nanocoulombs uniformly distributed on its surface. Location D i
kkurt [141]

The change in potential along a path from C to D due to a small charged sphere is 900 V.

Given:

Charge, Q = 3 nC = 3 × 10⁻⁹ C

Distance between the sphere and point C, r₁ = 0.02 m

Distance between the sphere and point D, r₂ = 0.06 m

Calculation:

We know that the electric potential is given as:

V = k Q/r   - (1)

where, V is the electric potential

            k is Coulomb's force constant

            Qis the charge on the  sphere

            r is the  separation distance

The electric potential at point C due to charged sphere can be given as:

V₁ = k Q/r₁

   = (9×10⁹ Nm²/C²) [(3 × 10⁻⁹ C)/(0.02 m)]

   = 1350 V

The electric potential at point D due to charged sphere can be given as:

V₂ = k Q/r₂

   = (9×10⁹ Nm²/C²) [(3 × 10⁻⁹ C)/(0.06 m)]

   = 450 V

Now, the change in potential along the path from C to D can be calculated as:

ΔV = V₂ - V₁

     = 450 V - 1350 V

     = -900 V

The negative sign indicates that the work is done against the electric field in moving the charge from C to D.

Therefore, the change in potential along a path from C to D is 900 V against the direction of the electric field.

Learn more about the electric potential here:

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#SPJ4

8 0
1 year ago
Read 2 more answers
Does anyone know the answer to all of these questions
Rasek [7]

Answer:

i don't understand the hw

5 0
3 years ago
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