Answer: The pressure in a liquid dec reaches with depth. F
The pressure in a liquid increases with depth.
The upthrust on an object is larger when it is deeper in a pool. 7
The bottom of a dam is thinner than the top of a dam. F
The bottom of a dam is thicker than the top of a dam.
The pressure is bigger at the bottom of a lake because of the weight of water above it. 7
I think these are the answers.
The heat form the Mylar outside her window may transfer the heat to the walls. Which then tanker the heat inside Lucia’s home.
Answer: C
Explanation: Amplitude controls loudness, and frequency controls pitch. The more frequent the higher pitch.
Answer:
ΔU = e(V₂ - V₁) and its value ΔU = -2.275 × 10⁻²¹ J
Explanation:
Since the electric potential at point 1 is V₁ = 33 V and the electric potential at point 2 is V₂ = 175 V, when the electron is accelerated from point 1 to point 2, there is a change in electric potential ΔV which is given by ΔV = V₂ - V₁.
Substituting the values of the variables into the equation, we have
ΔV = V₂ - V₁.
ΔV = 175 V - 33 V.
ΔV = 142 V
The change in electric potential energy ΔU = eΔV = e(V₂ - V₁) where e = electron charge = -1.602 × 10⁻¹⁹ C and ΔV = electric potential change from point 1 to point 2 = 142 V.
So, substituting the values of the variables into the equation, we have
ΔU = eΔV
ΔU = eΔV
ΔU = -1.602 × 10⁻¹⁹ C × 142 V
ΔU = -227.484 × 10⁻¹⁹ J
ΔU = -2.27484 × 10⁻²¹ J
ΔU ≅ -2.275 × 10⁻²¹ J
So, the required equation for the electric potential energy change is
ΔU = e(V₂ - V₁) and its value ΔU = -2.275 × 10⁻²¹ J
Answer:
A and B
Explanation:
The data sets that depict an accelerating object is Data Set A & Data Set B.
The both data sets show that the body is accelerating. Also, they show that the body started from rest (0m/s) at a 0sec.
Data Set A shows a non-constant acceleration which has changing amount of velocity with change in time. While Data Set B shows a constant acceleration which has constant amount of velocity with change in time.
