Answer:· Visible light passes through a diffraction grating that has 900 slits per centimeter, and the interference pattern is observed on a screen that is 2.74 m from the grating. In the first-order spectrum, maxima for two different wavelengths are separated on the screen by 3.16 m. What is the difference between these wavelengths? . I know to apply the equation din(theta) = m*wavelength but I'm not sure how to find all the missing variables or to get the difference in wavelengths
Answer: The correct answer is "Instrument A is placed closer to Sam than instrument B".
Explanation:
The sound can be soft or loud. Loudness depends on the amplitude of the sound wave. Higher the amplitude, more will be loudness. Lower the amplitude, lesser will be loudness.
Pitch depends on the frequency.
In the given problem, the instruments A and B generate sound waves of the same amplitude and at the same time.
Loudness depends on the sound energy produced as the energy of the sound is directly proportional to the square of the amplitude. It also depends on the distance between the source and the receiver.
Sam records a louder sound from instrument A than from instrument B. It means that there is mismatch in loudness. It can happen due to the placement of the instrument A closer to Sam than instrument B.
Therefore, the correct option is "Instrument A is placed closer to Sam than instrument B".
We see something as white, black, or another specific color because the object is reflecting light waves back.
In a nutshell; If we view an object as red, then the object is:
-> reflecting back red light waves
-> absorbing blue, green, etc light waves.
What about white and black?
We see white when most all of the light is reflected.
When there is little to no light reflected, we see black.