3 years ago

Y^2 + 16y= -39

1 answer:

8 0

$y^2 + 16y= -39\\
y^2+16y+39=0\\
y^2+13y+3y+39=0\\
y(y+13)+3(y+13)=0\\
(y+3)(y+13)=0\\
y=-3 \vee y=-13$

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