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balandron [24]
4 years ago
8

2019kL is the same as__dL?

Physics
1 answer:
Gwar [14]4 years ago
4 0
If kl is kiloliters and dl is deciliters, 2019kl=2.019e+7
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A mechanic pushes a 2.30 ✕ 103-kg car from rest to a speed of v, doing 4,800 J of work in the process. During this time, the car
Illusion [34]

The horizontal force applied is  160 N while the velocity is  2.03 m/s.

<h3>What is the speed of the car?</h3>

The work done by the car is obtained as the product of the force and the distance;

W = F x

F = ?

x = 30.0 m

W = 4,800 J

F = 4,800 J/30.0 m

F = 160 N

But F = ma

a = F/m

a = 160 N/2.30 ✕ 10^3-kg

a= 0.069 m/s

Now;

v^2 = u^2 + 2as

u = 0/ms because the car started from rest

v = √2as

v = √2 * 0.069 * 30

v = 2.03 m/s

Learn more about force and work:brainly.com/question/758238

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5 0
2 years ago
Which property of matter is conserved in chemical reactions and shown by balanced equations?
bezimeni [28]

Answer:

Mass.

Explanation:

I took the quiz and got the answer right

8 0
2 years ago
Read 2 more answers
Times will the kinetic one
mixer [17]

Answer:

The new kinetic energy is 9 times of the initial kinetic energy.

Explanation:

The kinetic energy of an object is given by the formula as follows :

E=\dfrac{1}{2}mv^2

Where

m is mass and v is speed of the body

If the speed of the body is tripled. Let v' is the new speed, v' = 3v. The new kinetic energy is E' and it is given by :

E'=\dfrac{1}{2}mv'^2\\\\\text{Put v' = 3v}\\\\E'=\dfrac{1}{2}m\times (3v)^2\\\\=\dfrac{1}{2}m\times 9v^2\\\\=9\times (\dfrac{1}{2}mv^2)\\\\E'=9\times E

Hence, the new kinetic energy is 9 times of the initial kinetic energy.

3 0
3 years ago
The diagram below shows the velocity vectors for two cars that are moving relative to each other.
scoundrel [369]

Answer:

The answer is "5 \ \frac{m}{s} \ west"

Explanation:

\to \vec{V_1} = (25 \frac{m}{s}) (\hat{-i})\\\\\to  \vec{V_2} = (20 \frac{m}{s}) (\hat{-i})\\\\

velocity of car | respect to car :

\to \vec{V_{12}} = \vec{V_1} - \vec{V_2}\\\\

          =\vec{-25} \hat{i}+ \vec{20} \hat{i}\\\\= 5 \ \frac{m}{s} \ west

7 0
3 years ago
A satellite in space has a mass of 252 kg. The engines on it provide a net force of 6.81×10-3 N. How long will it take for this
bearhunter [10]

Acceleration = (force) / (mass)

Acceleration = (6.81 x 10⁻³ N) / (252 kg)

Acceleration = 2.70 x 10⁻⁵ m/s²

Time = (change in v) / (acceleration)

Time = (262 m/s) / (2.70 x 10⁻⁵ m/s²)

<em>Time = 9,703,704 seconds</em>

That's  2,695.5 hours , or  112.3 mean solar Earth days .

7 0
3 years ago
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