U=RI Ohm's law
then R=U/I
=120/0.08
=2250Ω
hope this helps you
Answer:
The maximum height above the point of release is 11.653 m.
Explanation:
Given that,
Mass of block = 0.221 kg
Spring constant k = 5365 N/m
Distance x = 0.097 m
We need to calculate the height
Using stored energy in spring
...(I)
Using gravitational potential energy
....(II)
Using energy of conservation




Where, k = spring constant
m = mass of the block
x = distance
g = acceleration due to gravity
Put the value in the equation


Hence, The maximum height above the point of release is 11.653 m.
It was estimated, according to the United States Energy Information Administration, that the United States still consumes almost 91% of non-renewable resources as its energy source. In addition, 32 % of it are natural gas, 28 % for petroleum and crude oil, and 21 % for coal power.
Answer: I didn't see a difference because the large ball's vertical displacement and velocity are the same as the small one's.
Explanation:
Answer:
106.7 N
Explanation:
We can solve the problem by using the impulse theorem, which states that the product between the average force applied and the duration of the collision is equal to the change in momentum of the object:

where
F is the average force
is the duration of the collision
m is the mass of the ball
v is the final velocity
u is the initial velocity
In this problem:
m = 0.200 kg
u = 20.0 m/s
v = -12.0 m/s

Solving for F,

And since we are interested in the magnitude only,
F = 106.7 N