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goldenfox [79]
3 years ago
13

. If the combustion of 45.0 g of methane (natural gas) releases 2498 kJ of heat energy, how much heat

Chemistry
2 answers:
Amanda [17]3 years ago
6 0

Answer:

8.60 x 10⁴ kJ

Explanation:

The energy released per gram of methane is first calculated:

(2498kJ)/(45.0g) = 55.5 kJ/g

The heat released by the combustion of 1.55 kg of methane is then calculated:

(55.5kJ/g)(1.55kg)(1000g/kg) = 86025kJ

To three significant digits, the answer is 8.60 x 10⁴ kJ.

blondinia [14]3 years ago
5 0
45g ---> 2498kJ
1.55g ----> ?kJ
 Answer: (1.55x2498)/45 approx 86.04 (kJ)

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Explanation:

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Step-1

 Then,we will get,

Cr=\frac{1}{51.996} \times33.6=0.64 mol

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Step-2

Divide the mole value with the smallest number of mole, we will get,

Cr= \frac{0.64}{0.64} =1

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