1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anarel [89]
3 years ago
15

In the equation for final velocity with average acceleration, the final velocity is equal to the _____ velocity plus the product

of the average acceleration and time interval.
Physics
1 answer:
Dominik [7]3 years ago
4 0
INITIAL,INITIAL,INITIAL,INITIAL,
You might be interested in
If 1.34 ✕ 1020 electrons move through a pocket calculator during a full day's operation, how many coulombs of charge moved throu
ioda

Given :

Number of operations move through a pocket calculator during a full day's operation , n=1.34 \times 10^{20} .

To Find :

How many coulombs of charge moved through it .

Solution :

We know , charge in  one electron is :

e^-=-1.6\times 10^{-19}\ coulombs

So , charge on n electron is :

C=e^-\times n\\C=-1.6\times 10^{-19}\times 1.34\times 10^{20} \ C\\C=-21.44\ C

Therefore , -21.44 coulombs of charge is moved through it .

Hence , this is the required solution .

3 0
3 years ago
An apparatus like the one Cavendish used to find G has large lead balls that are 5.2 kg in mass and small ones that are 0.046 kg.
Ber [7]

Answer:

The magnitude of gravitational force between two masses is 4.91\times 10^{-9}\ N.

Explanation:

Given that,

Mass of first lead ball, m_1=5.2\ kg

Mass of the other lead ball, m_2=0.046\ kg

The center of a large ball is separated by 0.057 m from the center of a small ball, r = 0.057 m

We need to find the magnitude of the gravitational force between the masses. It is given by the formula of the gravitational force. It is given by :

F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67259\times 10^{-11}\times \dfrac{5.2\times 0.046}{(0.057)^2}\\\\F=4.91\times 10^{-9}\ N

So, the magnitude of gravitational force between two masses is 4.91\times 10^{-9}\ N. Hence, this is the required solution.

5 0
3 years ago
Please help!How is constant or uniform acceleration used to explain free fall?
garik1379 [7]
Free fall is a special case of motion with constant acceleration, because acceleration due to gravity is always constant and downward. For example, when a ball is thrown up in the air, the ball's velocity is initially upward.
4 0
2 years ago
Why are chemical changes considered “unseen”?
jeka57 [31]
<span>Because they occur at an atomic level, changing the actual structure of the thing.

</span>
7 0
3 years ago
Read 2 more answers
Convert 14 mg to kg ....<br>​
____ [38]
<h2>♨ANSWER♥</h2>

14mg = 14 × 10^-3 g

= 14 × 10^-3 / 10^3 kg

= 14 × 10^-6 kg

= 0.014 kg

<u>☆</u><u>.</u><u>.</u><u>.</u><u>hope this helps</u><u>.</u><u>.</u><u>.</u><u>☆</u>

_♡_<em>mashi</em>_♡_

7 0
1 year ago
Read 2 more answers
Other questions:
  • The force needed to accelerate a stationary 2000 racing car to a speed of 144 km/h in a distance of 80 meters
    14·1 answer
  • Cany anyone teach me how to use the vernier callipers?
    7·1 answer
  • Calculate the wavelengths of the first five members of the lyman series of spectral lines
    7·1 answer
  • What is the kinetic energy of a 10-kg bicycle moving at 10 m/s?​
    10·1 answer
  • A famous physics tale is about a rich man who was found dead. He was
    11·1 answer
  • Why is most space exploration accomplished with spacecraft that do not have astronauts on board
    6·2 answers
  • What was the first president of the United States
    15·1 answer
  • Oscillations of electricity and magnetism create ________________________ waves, which include visible light waves.
    14·1 answer
  • A bag of groceries is on the back seat of your car as you stop for a stop light. The bag does not slide. Apply your analysis to
    15·1 answer
  • A large tank is filled with water to a depth of 38 m. An opening is located 14 m
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!