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4 years ago

The inner solar system contains the

1 answer:

3 0

Jovian planets and dwarf planets like pluto are in the outer part of our solar system. so, terrestrial planets ,which means earth like planets, live in the inner part of our solar system. or B. is the answer

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Two trucks travel at the same speed. They are far apart on adjacent lanes and approach each other essentially head-on. One drive

kow [346]

Answer: 19.72m/s

Explanation:

Since we are considering the speed, the C in the formula can as well be represented with other letter V as one choses.

8 0

4 years ago

Why cant you feel the force attraction between mars

Ludmilka [50]

The distance is too great for the attraction to make a difference

6 0

3 years ago

How did the discovery of eris force astronomers to reconsider the definition of planet?

kogti [31]

Answer:

Explanation:

They had demoted Pluto on the basis of the discovery of Eris. They also discovered that Eris had a moon. It was thought to be much bigger than Pluto. That turned out not to be true. So having accepted Eris as a planet, they had to consider carefully what to do about Pluto. It has a gravitational constant of 0.82 m/s^2 which is 8.4% of that of our gravitational pull. and slightly more than Pluto.

Later data showed that these two objects in space were more like twins and that's what shook up the definition of a planet. You can't demote one and not the other.

5 0

3 years ago

A stone is thrown vertically upward with a speed of 15.5 m/s from the edge of a cliff 75.0 m high .

rjkz [21]

a) 2.64 s

We can solve this part of the problem by using the following SUVAT equation:

$s=ut+\frac{1}{2}at^2$

where

s is the displacement of the stone

u is the initial velocity

t is the time

a is the acceleration

We must be careful to the signs of s, u and a. Taking upward as positive direction, we have:

- s (displacement) negative, since it is downward: so s = -75.0 m

- u (initial velocity) positive, since it is upward: +15.5 m/s

- a (acceleration) negative, since it is downward: so a= g = -9.8 m/s^2 (acceleration of gravity)

Substituting into the equation,

$-75.0 = 15.5 t -4.9t^2\\4.9t^2-15.5t-75.0 = 0$

Solving the equation, we have two solutions: t = -5.80 s and t = 2.84 s. Since the negative solution has no physical meaning, the stone reaches the bottom of the cliff 2.64 s later.

b) 10.4 m/s

The speed of the stone when it reaches the bottom of the cliff can be calculated by using the equation:

$v=u+at$

where again, we must be careful to the signs of the various quantities:

- u (initial velocity) positive, since it is upward: +15.5 m/s

- a (acceleration) negative, since it is downward: so a = g = -9.8 m/s^2

Substituting t = 2.64 s, we find the final velocity of the stone:

$v = 15.5 +(-9.8)(2.64)=-10.4 m/s$

where the negative sign means that the velocity is downward: so the speed is 10.4 m/s.

c) 4.11 s

In this case, we can use again the equation:

$s=ut+\frac{1}{2}at^2$

where

s is the displacement of the package

u is the initial velocity

t is the time

a is the acceleration

We have:

s = -105 m (vertical displacement of the package, downward so negative)

u = +5.40 m/s (initial velocity of the package, which is the same as the helicopter, upward so positive)

a = g = -9.8 m/s^2

Substituting into the equation,

$-105 = 5.40 t -4.9t^2\\4.9t^2 -5.40 t-105=0$

Which gives two solutions: t = -5.21 s and t = 4.11 s. Again, we discard the first solution since it is negative, so the package reaches the ground after

t = 4.11 seconds.

5 0

3 years ago

Read 2 more answers

A boat crosses a river of width 229 m in which the current has a uniform speed of 0.756 m/s. The pilot maintains a bearing (i.e.

Stolb23 [73]

Answer:

1.85 m/s

102.438 m

Explanation:

From vector motion

The resultant velocity

$R=\sqrt{0.756^2+1.69^2}\\\Rightarrow R=1.85\ m/s$

The magnitude of speed of the speed of the boat relative to a stationary shore observer is 1.85 m/s

The distance covered is 229 m

Time = Distance / Speed

$\text{Time}=\frac{229}{1.69}\\\Rightarrow \text{Time}=135.50\ s$

Distance = Speed of current × Time

Distance = 0.756×135.5 = 102.438 m

The boat will be 102.438 m from the initial position is the boat when it reaches the opposite shore

3 0

4 years ago