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3 years ago

The inner solar system contains the

1 answer:

3 0

Jovian planets and dwarf planets like pluto are in the outer part of our solar system. so, terrestrial planets ,which means earth like planets, live in the inner part of our solar system. or B. is the answer

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1. A Passenger car (m= 10.0 kg) and a flat car (m= 7.5 kg) collide and move off as

grin007 [14]

Answer:

use a calculator to solve that

6 0

2 years ago

A bicycle is heading west. It goes 500m in 5 minutes. What is its velocity?

icang [17]

Speed = 500m/5min = 100 m/min. Direction = west. Velocity = 100 m/min west.

4 0

3 years ago

Read 2 more answers

A 1.7m long barbell has a 20kg weight on its left and a 35kg weight on its right. (a) If you ignore the weight of the bar itself

Levart [38]

Answer:

(a) 1.08 m

(b) 1.06 m

Explanation:

<u>Step 1:</u> calculate the center of gravity from 20kg mass

Let the center of gravity from 20kg mass = X

Applying the principle of moment; clockwise moment = ant-clockwise moment

20*X = 35*(1.7-X)

20X = 59.5 - 35X

55X = 59.5

X = 59.5/55

X = 1.08 m

Ignoring the weight of the bar, the center of gravity is 1.08m from left end of the barbell.

<u>Step 2:</u> calculate the center of gravity from 20kg mass, if the 8.0kg mass of the barbell in considered.

Applying the principle of moment

$(20*X)+\frac{X}{2}(\frac{8}{1.7}) = 35(1.7-X) + (\frac{1.7-X}{2})(\frac{8}{1.7})$

$20X + 2.353X = 59.5 -35X +2.353(1.7-X)$

20X +2.353X = 59.5 -35X + 4 - 2.353X

59.706X = 63.5

X = 63.5/59.706

X = 1.06 m

considering the weight of the bar, the center of gravity is 1.06m from left end of the barbell.

4 0

2 years ago

The usefulness of blotting techniques in molecular biology is that

densk [106]

Answer:

Transferred material is in the same relative position on the disk as on the original sample

Explanation:

The usefulness of blotting techniques in molecular biology is that transferred material is in the same relative position on the disk as on the original sample

3 0

3 years ago

Two gliders collide on a frictionless air track that is aligned along the x axis. Glider A has an initial velocity of +4.0 m/s a

DedPeter [7]

Answer:

As collision is elastic,thus we can use conservation of momentum equation

mA=0.2 kg

(vB)1=0 m/s.......................as it is on rest before collision

(vA)1=4 m/s

(vA)2=-1 m/s

(vB)2=2 m/s

using equation

(mA*vA+mB*vB)1= (mA*vA+mB*vB)2

Where 1 and 2 represents before and after collision

(0.2*4)+(mB*0)=(0.2*-1)+(mB*2)

0.8=-0.2+(2mB)

mass of object B=mB=0.3 Kg

6 0

3 years ago