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Phoenix [80]
3 years ago
8

The inner solar system contains the

Physics
1 answer:
Dominik [7]3 years ago
3 0
Jovian planets and  dwarf planets like pluto are in the outer part of our solar system. so, terrestrial planets ,which means earth like planets, live in the inner part of our solar system. or B. is the answer
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A rock dropped into a pond produces a wave that takes 11.3 s to reach the opposite shore, 26.5 m away. the distance between cons
Kay [80]
The wave takes 11.3 s to cover a distance of 26.5 m, so its speed is:
v= \frac{S}{t}= \frac{26.5 m}{11.3 s}=2.35 m/s

The distance between two consecutive crests is 3 m, and this corresponds to the wavelength of the wave. To find its frequency, we can use the relationship between the speed v, the wavelength \lambda and the frequency f:
f= \frac{v}{\lambda}= \frac{2.35 m/s}{3 m}=0.78 Hz
6 0
3 years ago
a city government received a $1 million grant to build swimming pools and skating rinks for youth. based on the data provided in
ivolga24 [154]

We have that for the Question "A city government received a $1 million grant to build swimming pools and skating rinks for youth. based on the data provided in the graph, what is the opportunity cost of building one swimming pool?" it can be said that

OC=2

From the question we are told

A city government received a $1 million grant to build swimming pools and skating rinks for youth. based on the data provided in the graph, what is the opportunity cost of building one swimming pool?

Generally the equation for the Opportunity cost  is mathematically given as

OC=\frac{y_1-y_2}{x_1-x_2}\\\\OC=\frac{2-0}{1-0}\\\\OC=2

Therefore

From the graph of the  question we can ascertain that Opportunity cost

OC=2

For more information on this visit

brainly.com/question/18670421

Graph is attached below

6 0
2 years ago
A satellite has a mass of 5832 kg and is in a circular orbit 4.13 × 105 m above the surface of a planet. The period of the orbit
elena55 [62]

Answer:

W = 28226.88 N

Explanation:

Given,

Mass of the satellite, m = 5832 Kg

Height of the orbiting satellite from the surface, h = 4.13 x 10⁵ m

The time period of the orbit, T = 1.9 h

                                            = 6840 s

The radius of the planet, R = 4.38 x 10⁶ m

The time period of the satellite is given by the formula

                             T = 2\pi \sqrt{\frac{(R+h)^{3} }{R^{2} g} }  second

Squaring the terms and solving it for 'g'

                             g = 4 π² \frac{(R+h)^{3} }{R^{2}T^{2}  }   m/s²

Substituting the values in the above equation

                   g = 4 π² \frac{(4.38X10^6+4.13X10^5)^{3} }{(4.38X10^6)^{2}X6840^{2}}  

                                    g = 4.84 m/s²      

Therefore, the weight

                                     w = m x g   newton

                                         = 5832 Kg x 4.84 m/s²

                                         = 28226.88 N

Hence, the weight of the satellite at the surface, W = 28226.88 N                

8 0
3 years ago
Help! I don’t really know what it’s asking
Misha Larkins [42]
You have to do the math of each and see which one adds up to 66.5
6 0
2 years ago
What is the shape of the earth's orbit around the sun?
Daniel [21]
<span>............D. Elliptical</span>
7 0
3 years ago
Read 2 more answers
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