To answer this question I would have to know the elements in the compound
Answer:A. Dilute copper and ascorbic acid solutions should be disposed of in the waste container in the hood.
C. Metal and graphite electrodes should be rinsed with water, dried, and returned to their positions on the lab bench.
D. The contents of the half-cell module should be disposed of in the waste container in the hood.
Explanation: An electrochemical cell is a cell that has the capability of producing Electric energy from chemical reaction (voltaic cells) or using Electric energy to make chemical reactions to take place(electrolytic cell). For a proper or effective waste disposal in an electrochemical cell the following options are correct.
Dilute copper and ascorbic acid solutions should be disposed of in the waste container in the hood.
Metal and graphite electrodes should be rinsed with water, dried, and returned to their positions on the lab bench.
The contents of the half-cell module should be disposed of in the waste container in the hood.
Answer:
Mass = 36.4 ×10⁻³ g
Explanation:
Given data:
Volume of container = 100 mL ( 100/1000 = 0.1 L)
Pressure = 688 mmHg (0.9 atm)
Temperature = 565°C ( 565 + 273 = 838 K)
Mass in grams of nitrogen = ?
Solution:
According to ideal gas equation,
PV = nRT
n = number of moles
P = pressure
R = general gas constant
T = temperature
From this equation we will determine the number of moles and then we we will calculate the mass.
n = PV/RT
n = 0.9 atm × 0.1 L / 0.0821 atm. L / mol.K × 838 K
n = 0.09 / 68.8
n = 0.0013 mol
or
n = 1.3×10⁻³ mol
Mass of nitrogen gas:
Mass = number of moles × molar mass
Mass = 1.3×10⁻³ mol × 28 g/mol
Mass = 36.4 ×10⁻³ g
Answer:
Outer electrons.
Explanation:
All bonds are localized bonds formed between two atoms by the donation of electrons from each atom.