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svetlana [45]
3 years ago
6

Which of the following is a luminous object? the Moon Jupiter a comet the Sun

Physics
2 answers:
fgiga [73]3 years ago
6 0
The Sun is the only luminous object on that list ... it has its own light.

Jupiter, the Moon, and comets are only visible when the Sun shines on them.
babunello [35]3 years ago
3 0
The Sun is a luminous object. 
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Consider two positively charged particles, one of charge q₀ (particle 0) fixed at the origin, and another of charge q₁ (particle
docker41 [41]

Answer:

Explanation: according to Coulomb's inverse-square law is proportional to the square of distance between them and is given by

F=k\frac{q_0q_1}{r^2}

where r is the distance between the charges & k is the Coulomb's constant

k=1/(4*ε_0*π)

k=9*10^9

the distance between the charges in this question is d_1

hence the magnitude of the force exerted by q_0 on q_1 is given by

F=k\frac{q_0q_1}{d_1^2}

due to location of particle 1 above the particle 0 the direction of force is parallel to y axis and in vector form

F=k\frac{q_0q_1}{d_1^2} j

4 0
3 years ago
Fluids can flow and change shape to fit their containers. Which two states are<br> fluids?
mr_godi [17]

Answer: the two states that are fluid are;-

<u>#{1} liquid</u>

<u>#{2} gas </u>

Explanation:

as we know that there are mainly three states of substance

but among them only two of them can fluid and takes the shape of the container that are liquid and gas

4 0
2 years ago
What is the magnitude of the Box's Acceleration?​
mojhsa [17]

The Box's Acceleration : g sin θ

<h3>Further explanation  </h3>

Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object  

∑F = m. a  

F = force, N  

m = mass = kg  

a = acceleration due to gravity, m / s²  

We plot the forces acting on the block (picture attached) according to the y-axis and the x-axis.

Because the motion of the block is in the same direction as the x-axis, ignoring the friction force with the inclined plane, then

\tt \sum F_x=m.a\\\\W.sin\theta=m.a\\\\mgsin\theta=m.a\\\\a=gsin\thet\theta

4 0
3 years ago
Kepler deduced this law of motion from observations of Mars. What information confirms his conclusion that the orbit of Mars is
Leno4ka [110]

Kepler noticed an imaginary line drawn from a planet to the Sun and this line swept out an equal area of space in equal times, If we then draw a triangle out from the Sun to a planet’s position at one point in time, it is notice that the area doesn't change even after the planet has left the original position say like after 2 to 3days or 2hours. So to have same area of triangle means that the the planet move faster when that are closer to the sun and slowly when they are far from the sun.

This led to Kepler's law of orbital motion.

First Law: Planetary orbits are elliptical with the sun at a focus.

Second Law: The radius vector from the sun to a planet sweeps equal areas in equal times.

Third Law: The ratio of the square of the period of revolution and the cube of the ellipse semi-major axis is the same for all planets.

It is this Kepler's law that makes Newton to come up with his own laws on how planet moves the way they do.

6 0
3 years ago
A block with mass m =6.4 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.28 m.
Zanzabum

Answer

given,

mass of block (m)= 6.4 Kg

spring is stretched to distance, x = 0.28 m

initial velocity = 5.1 m/s

a) computing weight of spring

    k x = m g

k = \dfrac{mg}{x}

k = \dfrac{6.4 \times 9.8}{0.28}

      k = 224 N/m

b) f = \dfrac{\omega}{2\pi}

    \omega = \sqrt{\dfrac{k}{m}}= \sqrt{\dfrac{224}{6.4}} = 5.92 \ rad/s

   f = \dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

   f = \dfrac{1}{2\pi}\sqrt{\dfrac{224}{6.4}}

  f =0.94\ Hz

c)  v_b = -v cos \omega t

    v_b = -5.1 \times cos (5.92 \times 0.42)

    v_b = 4.04\ m/s

d)  a_{max} = v \omega

    a_{max} = 4.04 \times 5.92

    a_{max} =23.94\ m/s^2

e)  Y =- A sin (\omega t)

    A = \dfrac{v}{\omega}

    A = \dfrac{4.04}{5.92}

        A = 0.682 m

    Y =- 0.682 \times sin (5.92 \times 0.42)

    Y =- 0.42

Force =m \omega^2 |Y|

          =6.4 \times 5.92^2\times 0.42

F = 94.20 N

4 0
3 years ago
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